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alexandr1967 [171]
3 years ago
14

I need help ASAP. Thank you (:

Mathematics
1 answer:
Anarel [89]3 years ago
3 0

Answer: volume = 1282.2 ft³

Step-by-step explanation:

The composite figure consists of a cone and a cylinder. The volume of the composite figure is

Volume of cylinder + volume of cone.

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

Radius = 7 ft

Height = 6 ft

Volume = 3.14 × 7² × 6 = 923.16ft³

The formula for determining the volume of a cone is expressed as

Volume = 1/3πr²h

From the information given,

Radius = 7 ft

Height = 7ft

Volume = 1/3 × 3.14 × 7² × 7 = 359ft³

Volume of composite solid =

923.16 + 359 = 1282.2 ft³

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Yanka [14]
Answer: 9 meters

To answer this question you need to know the formula to calculate the area of a square. Square has same side length so the area is: length x length.
Then the calculation would be:

Area= length x length
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Length ^2= 81 m2
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4 0
3 years ago
Evaluate the integral Integral from 0 to 1 Integral from 0 to 3 Integral from 3 y to 9 StartFraction 6 cosine (x squared )Over 5
Natalka [10]

Answer:

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Step-by-step explanation:

cosine x²= cos x²

Rule

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  • \int cos \ mx \ dx = \frac{sin \ mx}{m}+c
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Given that,

\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz

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=\int^1_0[\int^3_0([\frac{6cos x^2 \times \sqrt z}{5\times \frac{1}{2}}]^9_{3y})dy]dx

=\int^1_0[\int^3_0([\frac{12cos x^2 \times( \sqrt 9-\sqrt{3y})}{5}])dy]dx

=\int^1_0[\int^3_0([\frac{12cos x^2 \times( 3-\sqrt{3y})}{5}])dy]dx

=\int^1_0[\frac{12cos x^2 \times( 3y-\frac{\sqrt{3}y^\frac{3}{2}}{\frac{3}{2}})}{5}]^3_0dx

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=\int^1_0[\frac{12cos x^2 \times( 9-6)}{5}]dx

=\frac{18}{5}\int^1_02cos x^2dx

=\frac{18}{5}\int^1_0(1+cos2x)dx

=\frac{18}{5}[(x+\frac{sin2x}{2})]^1_0

=\frac{18}{5}(1+\frac{sin2}{2})

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3 years ago
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