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joja [24]
3 years ago
11

Complete the problems below.

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

1. NO

2. YES

3. YES

4. YES

5. NO

6. YES

7. NO

8. YES

9. YES

10. YES

11. NO

12. YES

13. YES

14. YES

15. 9, 8, 7, 6, 4, 3, and 2

16. 5 and 3

17. 5

18. 10, 5, and 2

19. 9, 6, 4, 3, and 2

20. 10, 8, 7, 6, 5, 4, 3, and 2

21. 10, 6, 5, 3, and 2

22. 10, 8, 7, 6, 5, 4, 3, and 2

23. 5

24. 7, 6, 4, 3, and 2

25. 6, 4, 3, and 2

26. 10, 5, 4, and 2

27. 9, 8, 6, 4, 3, and 2

28. 10, 9, 6, 5, 3, and 2

29. 8, 4, and 2

30. 8, 6, 4, 3, and 2

31. 22<u>7</u>043

32. 3<u>8</u>187

33. 1<u>5</u>111

34. 2032371

Step-by-step explanation:

<u>Divisibility Rules</u>

10 → The digit in the ones place value chart must be a 0.

9 → The sum of the digits must add up to a multiple of 9.

8 → The LAST THREE DIGITS of the entire number must be a multiple of 8.

7 → Take the ones place value digit off the entire number, double it, then deduct the doubled number from the remaining number. NOTE: This may need to be repeated several times.

6 → The entire number must be a multiple of BOTH 3 and 2 [Here is the catch: 2 × 3 = 6]

5 → The digit in the ones place value chart must be a 0 or 5.

4 → The LAST TWO DIGITS of the entire number must be a multiple of 4.

3 → The sum of the digits must add up to a multiple of 3.

2 → The digit in the ones place value chart must be a 0, 2, 4, 6, or 8.

I hope all this information can be put into some good use, and as always, I am EXTREMELY joyous to assist anyone at any time.

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Answer:

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Step-by-step explanation:

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The function is meaningless after the time the object comes to rest on the ground, so the domain of the function extends from 0 until that time.

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The true statements are C and E.

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