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Makovka662 [10]

3 years ago

15

In △ABC m∠CAB = 40° and m∠ABC = 60°. Circle, going through points A and C, intersects sides AB and BC in points D and E respecti

vely. Find all angles in quadrilateral ACED.

1 answer:

Gnom [1K]3 years ago

4 0

Answer:

80, 100

Step-by-step explanation:

180 - (40+60) =

80

That means one of the angles is 80, making an other angle 180-80 = 100 degrees

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Differentiate f and find the domain of f. (enter the domain in interval notation.)f(x) = ln(x2 − 12x)derivative f '(x) = 2x−12x2

guajiro [1.7K]

F(x) = ln(x² - 12x)
The derivative is
$f'(x)= \frac{2x-12}{x^{2}-12x}$

f(x) is undefined when x² - 12x = x(x - 12) = 0
That is, when x = 0 or x = 12.
Therefore the domain is (-∞, 0)∪(0,12)∪(12, ∞)

Answer:
The derivative is
$f'(x) = \frac{2x-12}{x^{2}-12x}$
The domain is
(-∞, 0)∪(0, 12)∪(12,∞)

3 0

3 years ago

I need help please

Dima020 [189]

It's either A or D.

6 0

3 years ago

Read 2 more answers

12 / 0.96 please answer this i need it

dimaraw [331]

Answer:

12.5

Step-by-step explanation:

4 0

3 years ago

A circle has its center at the origin, and (5, -12) is a point on the circle. How long is the radius of the circle?

aivan3 [116]

Hello here is a solution :
<span> the radius of the circle is OA A(5;-12) and O (0;0)
OA= </span><span>  square root ((5-0)² + (-12-0)²)
</span> = <span>  square root (25+144)
</span> = <span>  square root(169)
</span> OA = 13

7 0

3 years ago

Read 2 more answers

Determine the first five iterates of f(x) = 1.5x(1 _ x) for x0 = 0.8. (1 point)

Luden [163]

<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
f(0.24) = 1.5(0.24)(1 - 0.24) ~= 0.274
f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
f(0.298) = 1.5(0.298)(1 - 0.298) ~= 0.314
f(0.314) = 1.5(0.314)(1 - 0.314) ~= 0.323

</span>So the answer is D : 0.24, 0.274, 0.298, 0.314, 0.323

8 0

3 years ago