(f o g)(x) = f(g(x)) so we plug in the equation for g(x) where the x-variable is in f(x).
5(x + 1)³
5[(x + 1)(x + 1)(x + 1)]
5[(x² + 2x + 1)(x + 1)]
5(x³ + 3x² + 3x + 1)
(f o g)(x) = 5x³ + 15x² + 15x + 5
Answer:
f(x) = -4x²+24x -28
Step-by-step explanation:
The given zeros are a sum and a difference. You can use the special factoring of the product of a sum and difference to simplify the product of the factors of the quadratic. Each zero 'p' corresponds to a factor (x -p):
f(x) = a(x -(3 +√2))(x -(3 -√2)) = a((x -3)² -(√2)²) = a((x -3)² -2)
We can find the leading coefficient 'a' from the given point:
f(1) = -8 = a((1 -3)² -2) = 2a
a = -8/2 = -4
Then the function can be written as ...
f(x) = -4((x -3)² -2) = -4(x² -6x +9 -2)
f(x) = -4x²+24x -28
Answer:
Correct choice is D
Step-by-step explanation:
The i-th term of the binomial expansion is
If i=8, then
Answer:
13,800,000
Step-by-step explanation: