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4 years ago

Anybody know the answer plzzz i need help

Mathematics

1 answer:

alexandr1967 [171]4 years ago

6 0

B, there is no angles so it has to be SSS

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Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

<u>Answer:</u> The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

<u>Step-by-step explanation:</u>

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

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3 years ago

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vovikov84 [41]

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The number of blue fish to red fish in a tank is

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If there is 34 to 50 blue to red fish in tank A. Then tank B is 51 to 75. Because 75 is 1.5 times larger than 50 you have to multiply 34 by 1.5 to get 51.

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