3 years ago

Anybody know the answer plzzz i need help

Mathematics

1 answer:

alexandr1967 [171]3 years ago

6 0

B, there is no angles so it has to be SSS

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If 12g of a radioactive substance are present initially and 8yr later only 6g remain, how much if the substance will be present

Brums [2.3K]

The weight of substance remaining after 13 years is 2.25 g.

Given:

Present weight of substance = 12 g

After 8 years weight remains = 6 gm

Now, weight loss in 8 year will be,

12-6=6 gm

So, weight loss in 1 year will be,

$\dfrac{6}{8} =\dfrac{3}{4}$

Total weight loss in 13 year will be,

$\dfrac{3}{4}\times13=9.75$

The weight of substance remaining after 13 years will be,

$12- 9.75 = 2.25 \;\rm g$

Therefore, the weight of substance remaining after 13 years is 2.25 g.

To know more about radioactive decay, refer to the link:

brainly.com/question/12116123

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2 years ago

Find the output for each input of y = 2x – 1.

Jlenok [28]

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3) The first is a direct variation since y=6x is true.
4)The airplane would be 132ft in real life.
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3 years ago

Need help asap dont know how to do it

dimulka [17.4K]

Division. Divide 45 by -3

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2 years ago

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Quick question: is this correct?

blsea [12.9K]

Answer:

aha