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Amanda [17]
3 years ago
13

1/7 12% 9/100 88% 0.02 0.9 least to greatest

Mathematics
1 answer:
Archy [21]3 years ago
4 0

Answer:

Step-by-step explanation:

0.02, 9/100, 1/7, 0.9, 12%, 88%

sorry if the 0.9 is wrong, if it is then its most likely gonna be after 88%

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The point A(–1, 4) is translated five units right and three units down. Which rule describes the translation?
lozanna [386]

Answer: SECOND OPTION.

Step-by-step explanation:

Given the following point identified as "A":

A(-1,4)

You can identify that the x-coordinate of the point is:

x=-1

And its y-coordinate is:

y=4

According to the exercise, this point is translated five units right and three units down. This means that, in order to find the new coordinates, you need to add 5 to the original x-coordinate and subtract 3 from the original y-coordinate.

Therefore, you can conclude that the rule that best describe the translation of the point A(-1,4) is the following:

(x,y) → (x+5,y-3)

Then, the point translated is:

A'(-1+5,\ 4-3) → A'(4,1)

6 0
3 years ago
Read 2 more answers
Tell whether each statement is a proportion:
erma4kov [3.2K]

Answer:

1. Yes

2. No

3. No

4. No

5. Yes

Step-by-step explanation:

Do you mean equal proportion?

1. 3 : 9 = 6 : 18 TRUE because 3 : 9 = 1 : 3 and 6 : 18 = 1 : 3

2. 28 : 7 = 64 : 16 FALSE because they are just not related.

3. 95 : 100 = 17 : 20 FALSE because the closest they get are 19 : 20 ≠ 17 : 20

4. 60 : 80 = 14 : 16 FALSE because the closest they get are 60 : 80 = 6 : 8 and 14 : 16 = 7 : 8

5. 200 : 300 = 24 : 36 TRUE because 200 : 300 = 2 : 3 and 24 : 36 = 2 : 3

6 0
3 years ago
Eddie built the ramp shown to train his puppy to do tricks. What is the surface area of the ramp. The dimensions are 20,20,20,23
mamaluj [8]

Answer:

3775 in²

Step-by-step explanation:

The surface area of the ramp :

Area of rectangle = 20 * 23 = 460 in²

Area of rectangle = 20 * 23 = 460 in²

Area of rectangle = 25 * 23 = 575 in²

Bottom rectangle = 60 * 23 = 1380 in²

For the trapezium: (front and rear)

1/2 (base 1 + base 2) * height

Base total = 20+ 20+ 20= 60

1/2(60)*15 = 450 in²

Total surface Area :

(460 + 460 + 575 + 1380 + 450 + 450) in² = 3775 in²

6 0
3 years ago
Help me pls imma fail
KatRina [158]

Answer:

-

Step-by-step explanation:

3 0
2 years ago
A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o
balu736 [363]

Answer:

a

P(X \ge 1) = 0.509

b

P(X  \ge 1) = 0.6807

Step-by-step explanation:

From the question we are told that

   The number of students in the class is  N  =  20  (This is the population )

   The number of student that will cheat is  k =  3

   The number of students that he is focused on is  n  =  4

Generally the probability distribution that defines this question is the  Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally  probability mass function is mathematically represented as

      P(X = x) =  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}

Here C stands for combination , hence we will be making use of the combination functionality in our calculators  

Generally the that  he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

      P(X \ge 1) =  1 - P(X \le 0)

Here  

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{20 - 3} C_{4- 0}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{17} C_{4}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ 1 *  2380}{ 4845}

    P(X \le 0) =  0.491

Hence

    P(X \ge 1) =  1 - 0.491

     P(X \ge 1) = 0.509

Generally the that  he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

    P(X \ge 1) =  1 - P(X \le 0)

   P(X  \ge 1) =1- [  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]

Here n =  6

So

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{1  *  12376}{38760}]

    P(X  \ge 1) =1- 0.3193

    P(X  \ge 1) = 0.6807

   

5 0
3 years ago
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