8x^2-3 = sqrt(16x+9)
[8x^2-3]^2 = [sqrt(16x+9)]^2 ... square both sides
64x^4-48x^2+9 = 16x+9
64x^4-48x^2+9-16x-9 = 0
64x^4-48x^2-16x = 0
16x(4x^3-3x-1) = 0
16x(x-1)(2x+1)^2 = 0
16x=0 or x-1=0 or (2x+1)^2 = 0
x=0 or x=1 or x = -1/2
The possible solutions are x=0 or x=1 or x = -1/2
We need to check all the possible solutions
Checking x=0
8x^2-3 = sqrt(16x+9)
8(0)^2-3 = sqrt(16*0+9)
-3 = 3
The equation is false so x=0 is extraneous (not a real solution)
Checking x=1
8x^2-3 = sqrt(16x+9)
8(1)^2-3 = sqrt(16*1+9)
5 = 5
Equation is true. The value x=1 is a solution
Checking x=-1/2
8x^2-3 = sqrt(16x+9)
8(-1/2)^2-3 = sqrt(16(-1/2)+9)
-1 = 1
The equation is false so x=-1/2 is extraneous (not a real solution)
Therefore, the only answer is choice A) 1
Answer:
15
Step-by-step explanation:
Answer:
Hi,Do you still have geometry ??
Step-by-step explanation:
Answer:
x = 5. I dont know if this is what your looking for but good luck.
Step-by-step explanation:
I got this question too and x = 5 was correct
The area of a circle is represented by the equation:
We know that the diameter is two times the radius: 
So if we know that the diameter of the circle is 24m, we can divide this by two in order to get the radius:
-->
So then we can plug this radius in to the equation for the area of a circle:
We are told to use 3.14 as pi, and not pi itself, so let's plug in 3.14 for pi:
Now we know that the area of this circle is 452.16 square meters.
