All categories

2 years ago

What is the area of a circle with a radius of 6 inches?

Mathematics

2 answers:

lapo4ka [179]2 years ago

7 0

Answer:

idk

Step-by-step explanation:

Triss [41]2 years ago

7 0

Answer:

36π in.²

Step-by-step explanation:

The formula for the area of a circle is πr^2:

So, in our case, we can just substitute 6 for r:

π · 6² = 36π in.²

So 36π in.² or the third option is our answer

You might be interested in

Solve 8p = 40 using mental math A 32 B6 C 5 D 4

Anastaziya [24]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

5. REINFORCE Construct a 4th-degree polynomial with the following characteristics:

Eva8 [605]

A

- Harvard university professor

5 0

2 years ago

If y varies directly as x, and x = 48 when y = 6, find y when x = 12.

pentagon [3]

Answer: Each time the pentagon is rotated , it maps back onto itself. There are five values of for which the pentagon maps back onto itself. This is the same as the number of sides of the pentagon.

6 0

3 years ago

Read 2 more answers

Arrange the polynomial so that the powers of x are in descending order.

Aleonysh [2.5K]

8x - 9x²y + 7y² - 2x⁴
-2x⁴ - 9x²y + 8x + 7y²

3 0

3 years ago

If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b

MAXImum [283]

We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as x gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if a = 1 and b = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

3 0

2 years ago

What is the area of a circle with a radius of 6 inches?​

What is the area of a circle with a radius of 6 inches?