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3 years ago

Sams scooter charges $30 +$8per hour rosie's charges $20 fee +$10 per hour

1 answer:

7 0

The base fee ($30 & $20) are the independent variables.

An independent variable is a variable that does not depend on others

$8 & $10 depend on the number of hours so that is not the independent variable

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PLEASE AWNSER NEEDED NOW Find the volume of the figure. Round your answers to the nearest hundredth, if necessary

Margaret [11]

Didn’t you get that correct?

3 0

2 years ago

Solve 15x+3y=9,10x+7y=-4

TiliK225 [7]

Answer:

x = 1, y = -2

Step-by-step explanation:

15x + 3y = 9 (1)

10x + 7y = -4 (2)

3 × (2) - 2 × (1)

3 × (2)

30x + 21y = -12 (3)

2 × (1)

30x + 6y = 18 (4)

(3) - (4)

15y = -30

y = -30 / 15

y = -2

sub y = -2 into (1)

15x + 3y = 9

15x + (3 × -2) = 9

15x - 6 = 9

15x = 9 + 6

15x = 15

x = 15 / 15

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4 0

3 years ago

Find the area of the triangle

Brrunno [24]

Answer:

the answer is 108 ft²

Step-by-step explanation:

multiple 18 to 6

5 0

2 years ago

Read 2 more answers

Computer purchases: Out of 809 large purchases made at a computer retailer, 347 were personal computers, 398 were laptop compute

Luda [366]

Step-by-step explanation:

personal- 347 ÷ 809 = 0.43%

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6 0

3 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago