PLEASE HELP ME I need it ASAP

Andre is designing a website that will display reviews of school lunches. Each item on the menu is rated from 0 to 5 stars. The

Naddik [55]

Answer:

1. some good reasons are that put the most reviewed lunch at the top and good reasons to change it is that if you change it you could get more reviewers 2. yes it is representative of the population

Step-by-step explanation:

I hope it helps :-)

3 0

2 years ago

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

5 0

3 years ago

Read 2 more answers

Which is the BEST estimate of the average rate of change for the function graphed, over the interval 1 sxs 3?

jek_recluse [69]

Answer: -3

Step-by-step explanation: just multiply

7 0

3 years ago

A guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.

frutty [35]

Answer:

The length of the wire is 76.19 m.

Step-by-step explanation:

It is given that a guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.

It means base of the right angled triangle is 40 m.

The wire makes an angle of 58deg 20min with the ground.

1 degree = 60 min

Using this conversion convert the given angle in degree.

$58^{\circ}20'=58^{\circ}\frac{20}{60}^{\circ}=58\frac{1}{3}^{\circ}=\frac{175}{3}^{\circ}$

In a right angled triangle

$\cos \theta=\frac{adjacent}{hypotenuse}$

$\cos (\frac{175}{3}^{\circ})=\frac{40}{hypotenuse}$

$0.525=\frac{40}{hypotenuse}$

$hypotenuse=\frac{40}{0.525}$

$hypotenuse=76.190$

Therefore the length of the wire is 76.19 m.

3 0

3 years ago

Find the new amount if the original amount is 74 degrees and the percent of decrease is 3%. Round to the nearest tenth. Show all

saul85 [17]

Answer:

71.78? (not sure)

Step-by-step explanation:

To find 3% of 74, 74*.03 = 2.22

Subtract 3%, 74-2.22 = 71.78

4 0

3 years ago