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VLD [36.1K]
3 years ago
12

125.663 in terms of pi

Mathematics
1 answer:
noname [10]3 years ago
5 0

Just divide by pi, so it would be about 39.999(Pi)

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Elanso [62]

Answer:1/2

Step-by-step explanation:

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In trapezoid ABCD with bases AB and DC , diagonals intersect at point O. Find the length of diagonal BD , if BO=6 cm and: AO/OC
aalyn [17]

Answer:

8 cm

Step-by-step explanation:

... BO/OD = AO/OC = 3/1

Written another way, this is ...

... OD : BO = 1 : 3

Now, BD = OD + BO, so we have

... BD : BO = (OD +BO) : BO = (1 +3) : 3 = 4 : 3

That is, BD = 4/3 × BO

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3 years ago
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Scorpion4ik [409]

So here are 4 rules when it comes to exponents:

  1. When you raise a power to a power, you really just multiply the exponents: (x^m)^n=x^{m*n}
  2. When you multiply 2 exponents of the same base, you add the exponents together: x^m*x^n=x^{m+n}
  3. When you divide 2 exponents of the same base, you subtract the exponents: \frac{x^m}{x^n}=x^{m-n}
  4. To convert a negative exponent into a positive one, flip it to its reciprocal: x^{-m}=\frac{1}{x^m}\\ \frac{1}{x^{-m}}=\frac{x^{m}}{1}=x^m

<u>Part A:</u>

\frac{2x^3y^3}{4y^2}=\frac{1}{2}x^{3-0}y^{3-2}=\frac{1}{2}x^3y

<u>Part B:</u>

(\frac{x^{-8}}{y^{11}})^{-2}=\frac{x^{-8*-2}}{y^{11*-2}}=\frac{x^{16}}{y^{-22}}=\frac{x^{16}y^{22}}{1}=x^{16}y^{22}

<u>Part C:</u>

\frac{(2x^3)(x^4)^2}{8x^{11}}=\frac{(2x^3)(x^{4*2})}{8x^{11}}=\frac{(2x^3)(x^8)}{8x^{11}}=\frac{2x^{3+8}}{8x^{11}}=\frac{2x^{11}}{8x^{11}}=\frac{1}{4}x^{11-11}=\frac{1}{4}x^0=\frac{1}{4}

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3 years ago
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AnnZ [28]

In the "1s" place,

1₅ + 3₅ = 4₅

In the "5s" place,

2₅ + 4₅ = (6)₅ = (5 + 1)₅ = 10₅ + 1₅ = 11₅

In the "25s" place, we carry the leading 1 from the "5s" place,

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In the "125s" place, we carry over the 1 again,

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Answer:

Step-by-step explanation:

it is d

i took the test

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