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pogonyaev
4 years ago
12

Write the equation in slope-intercept form that contains the following point and is perpendicular to the given line

Mathematics
1 answer:
Len [333]4 years ago
8 0

Answer:

y = 1/4 x -3

Step-by-step explanation:

y = -4x + 3;

the slope of this equation is -4

we want the slope perpendicular to this

take the negative reciprocal

- (-1/4) = 1/4

so the slope of our line will be 1/4

we have the slope and a point so we can use point slope form

y-y1 = m (x-x1)

y--2 = 1/4(x-4)

y+2 = 1/4 (x-4)

we need to change it to slope intercept form (y=mx+b)

distribute

y+2 = 1/4 x -1/4*4

y+2 = 1/4x -1

subtract 2 from each side

y +2-2 = 1/4 x -1-2

y = 1/4 x -3

the slope is 1/4 and the y intercept is -3

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Read 2 more answers
PLS SOMEONE LOOK AT THE PHOTO I POSTED AND ANSWER AS SOON AS POSSIBLE PLS ITS ASKING FOR X= AND Y= NOT AN EQUATION JUST PLS ANSW
34kurt

We can solve it, but we can't actually use the interactive system they want you to use.  Let's see if we can guide you through it.

My guess is you can control the lines by dragging the two points on the line.

Let's make the green line y = 2x + 3

When x=0 we get y=3, point (0,3).   That's the y intercept, 3 up on the y axis.  Drag one green point there.

When x=2 we get y=7, point (2,7), two to the right, seven  up.  Drag the other green point there.   The green line is now y = 2x + 3.

Similarly the red line is made y = -3x + 3.    When x=0, y=3, point (0,3).  [Surprise!]   When x=2, y=-3, point (2,-3).  Drag the red points to (0,3) and (2,-3).

We already saw where they meet, at (0,3), x=0, y=3, the y intercept of both lines.

Answer: x=0, y=3

8 0
4 years ago
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