Given :
Devin is buying 2 concert tickets. The concert tickets have a regular price of $40 each.
Devin has a coupon that gives a 5% discount off of the regular price of the tickets. He will then pay a 10% purchasing fee on the discounted price of the tickets.
To Find :
Devin's total cost of the two tickets after the discount and the fee.
Solution :
Discount on price, D = 40×0.05 = $2 .
Price of product after discount, P = $( 40 - 2 ) = $38 .
Now, total price after adding purchasing fee is :
T = P + (P×0.10)
T = 38 + (38×0.10)
T = 38 + 3.8
T = $41.8
Therefore, Devin's total cost of the two tickets after the discount and the fee is $41.8 .
Hence, this is the required solution.
Given: Shandra can do the complete work in 45 minutes.
So, Shandra's 1-minute work = 1 / 45 and
Kelly can do the same complete work in 1 hour and 15 minutes = 75 minutes.
So, Kelly's 1-minute work = 1 / 75
Now, we shall calculate Shandra's and Kelly's 1-minute work
By both 1 minute work = (1/45) + (1 / 75) = 8 / 225
∵ 8 /225 Parts can be completed by both = in 1 minute
∴ Complete work (1) can be completed by both = 225 / 8 minutes
or, = in 28 minutes and 7.5 second
Hence, the assumption taken by both was incorrect.
The best described time will be 28 minutes and 8 seconds.
X=number of adults, y= number of students
x+y=12
18x+12y=162
You can simplify the second equation by dividing by six: 3x+2y=27
Rearrange the first equation: y= 12-x. Plug y into the simplified second equation:
3x+2(12-x)=27
3x-2x+24=27
x=3.
Plug the now known x value into y=12-x. So y= 9.
Therefore, there are 3 adults and 9 students.
Answer:
Assume the pair of dice are fair; if not, all bets are off!
Color one die green (G) and the other one red (R). There are 36 possibilities in throwing one green and one red die, eg (G1, R1), (G1, R2), etc; (G2, R1), (G2, R2), etc; etc; (G6, R1), (G6, R2), etc.
In the set of possible numbers from throwing a die, there are only 3 possibilities that sum to to 4: (G1, R3), (G2, R2), (G3, R1).
So the answer is 3/36, or one-twelfth.
