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Temka [501]
3 years ago
6

Which ordered pair makes both inequalities true? y < 3x – 1 y > –x + 4 On a coordinate plane, 2 straight lines are shown.

The first dashed line has a positive slope and goes through (0, negative 1) and (1, 2). Everything to the right of the line is shaded. The second solid line has a negative slope and goes through (0, 4) and (4, 0). Everything above the line is shaded. (4,0) (1,2) (0,4) (2,1)

Mathematics
2 answers:
Julli [10]3 years ago
9 0

Answer:

the answer is (4,0)

Step-by-step explanation:

It is (4,0) because it is on the solid line.:)

HOPE this Helps you

STAY SAFE

Katen [24]3 years ago
5 0

Answer:

(4,0)

Step-by-step explanation:

we have

y< 3x-1 ----> inequality A

y \geq -x+4 ----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

Verify each ordered pair

case 1) (4,0)

<em>Inequality A</em>

0< 3(4)-1

0< 11 ----> is true

<em>Inequality B</em>

0 \geq -(4)+4

0 \geq 0 ----> is true

so

the ordered pair makes both inequalities true

case 2) (1,2)

<em>Inequality A</em>

2< 3(1)-1

2< 2 ----> is not true

so

the ordered pair not makes both inequalities true

case 3) (0,4)

<em>Inequality A</em>

4< 3(0)-1

4< -1 ----> is not true

so

the ordered pair not makes both inequalities true

case 4) (2,1)

<em>Inequality A</em>

1< 3(2)-1

1< 5 ----> is true

<em>Inequality B</em>

1 \geq -(2)+4

1 \geq 2 ----> is not true

so

the ordered pair not makes both inequalities true

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