Answer:
<h2>
s(t) = 11t²/2 </h2>
Step-by-step explanation:
Velocity is defined as the rate of change in displacement of a body. It is expressed mathematically as v = change in displacement/time
v(t) = ds(t)/dt
ds(t) = v(t)dt
integrating both sides;
s(t) = 
Given the velocity function f(t) = 11t, the car's position (displacement) is expressed as s(t) = 
s(t) = 11t²/2 + C
at the initial point, s(0) = 0 i.e when t = 0, s(t) = 0. The resulting equation becomes;
0 = 11(0)²/2+ C
0 = 0+C
C = 0
To find the car's position, s(t), we will substitute C = 0 into the equayion above;
s(t) = 11t²/2 + 0
s(t) = 11t²/2
Hence s(t) = 11t²/2 is the required position of the car in terms of t.
246 rule -10
246, 236, 226, 216, 206...
The answer is A, 236
<span>(4x - 1) + (-5x + 17)
=4x-1-5x+17
= -x +16</span>
f(x)= 9x^3+ 2x^2 -5x+ 4
g(x)= 5x^3 -7x+ 4
f(x) - g(x)
= (9x^3+ 2x^2 -5x+ 4) - (5x^3 -7x+ 4)
= 9x^3+ 2x^2 -5x+ 4 -5x^3+ 7x -4
= (9x^3 -5x^3)+ 2x^2+ (7x -5x)+ (4-4) (combine like terms)
= 4x^3+ 2x^2+ 2x
= 2x* (2x^2+ x+ 1)
The final answer is 2x* (2x^2+ x+ 1).
You can just add the terms:
<span>(-x^2+9)+(-3x^2-11x+4) = -4x</span>² - 11x + 13