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4 years ago

Is the following relation a function ?

Mathematics

1 answer:

Sedaia [141]4 years ago

7 0

No it is not a function the are two inputs for one output

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The maximum load of a horizontal beam that is supported at both ends varies jointly as the width and the height and inversely as

dezoksy [38]

Answer:

$360kg$

Explanation:

Here, we want to get the maximum load supported

From the first part of the question, we have it that:

The maximum load g, varies jointly with the width w and the height h, and inversely as the length l between the supports

Mathematically, we have that as:

$g\text{ = k }\times\frac{wh}{l}$

where k is the proportionality constant

Now, let us get the value of k

We substitute the first set of values as follows:

$\begin{gathered} 360\text{ = }\frac{k\times0.1\times0.06}{6} \\ \\ k\text{ = 360,000 }\frac{kg}{m} \end{gathered}$

Now, using this value of k, we want to get the value of g

Mathematically, we have that as:

$g\text{ = }\frac{360,000\times0.2\times0.08}{16}\text{ = 360 }kg$

8 0

1 year ago

Select all the values that belong to the solution set of 9 ≤ 6 - y.

topjm [15]

9 < = 6 - y
9 - 6 < = -y
3 < = -y
-3 > = y or y < = -3

solutions include : -3,-4,-6

7 0

3 years ago

Can someone please help me with this? I'll give brainliest :)

vlabodo [156]

The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

<h3>How to determine the slope?</h3>

The interval is given as:

x = 2 to x = 5

The slope is calculated as:

$m = \frac{y_2 -y_1}{x_2-x_1}$

Substitute 2 and 5 for x

y = 3*2 - 4 = 2

y = 3*5 - 4 = 11

So, we have:

$m = \frac{11 - 2}{5 - 2}$

$m = \frac{9}{3}$

Divide

m = 3

Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3

Substitute 2 and 5 for x

y = 2 * 2^2 - 4 * 2 - 2 = -2

y = 2 * 5^2 - 4 * 5 - 2 = 28

So, we have:

$m = \frac{28 + 2}{5 - 2}$

$m = \frac{30}{3}$

Divide

m = 10

Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10