<span>(-6,0) would be correct </span>
See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid
we know that
One edge of the cuboid has length 2 cm-----> <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1
[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]
100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm
<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm
the answer is the length of a diagonal of the cuboid is 13.75 cm
Answer:
A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct
Step-by-step explanation:
step 1
Find the area of the base of the rectangular pyramid
we know that
The volume of the rectangular pyramid is equal to

where
B is the area of the base
H is the height of the pyramid
we have


substitute and solve for B



step 2
Find the volume of the rectangular prism with the same base area and height
we know that
The volume of the rectangular prism is equal to

we have


substitute

therefore
The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct
Answer:
$1,792
Step-by-step explanation:
3 1/2×36.40=116.48
116.48÷6.5%=1,792
$1,792
6.7*6.7 to find the surface area of the base which is 44.89
4*1/2*10.1*6.7 to fix the surface area of all four triangular faces which is 135.34
Plus them together 44.89+135.34 which is 180.23