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Pachacha [2.7K]
3 years ago
9

Could somebody help me I don't understand this? and can you explain how you did it.​

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0

Answer:

77°F

Step-by-step explanation:

C = 5/9 (F - 32)

25 = 5/9 (F - 32)

-----------------------

        5/9

45 = F - 32

+32       +32

------------------

77=F

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Step-by-step explanation:

Yes.

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Answer and Step-by-step explanation:

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This writing prompts is hard
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A.) Simplifying the equation would lead you to 15x^2-3x+9

b.) You know your answer is correct because you're adding the two polynomials together. 9x^2+6x^2 is 1tx^2. Now you have 2x-5x and since the negative is bigger, you get -3x. Then 5+4 is 9. You have no like terms therefore your answer is 15x^2-3x+9
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The interior angles of a triangle have measures 90°, 48°, and xº.<br> What is the value of x?
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Step-by-step explanation:

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3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

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which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

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b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

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3 years ago
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