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Julli [10]
3 years ago
13

Taletha is preparing for an exam in Algebra II. She knows she will be expected to determine if two functions are inverses of eac

h other using composition of functions. Which compositions would she use to prove f(x) and g(x) are inverse functions?
f ○ g(x) = and g ○ f(x) =

⊝


f ○ g(x) = x and g ○ f(x) =

⊝


f ○ g(x) = x and g ○ f(x) = x

⊝


f ○ g(x) = and g ○ f(x) = x
Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

f ○ g(x) = x and g ○ f(x) = x  is the correct composition

Step-by-step explanation:

INVERSE FUNCTIONS: Two functions are said to be inverse of each other if for every y = f(x), there exists a function g(x),

such that x = f^{-1} (y) =  g(y)

Now, here if we need to show tha two functions f(x) and g(x) are inverse functions of each other , then show that for every x:

1. f  o g(x)   =   f(g(x))= x

2. g o f(x)  =  g(f(x))   = x

If any two functions satisfy these two conditions, then they are inverse of each other.

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Alex787 [66]

Answer:

this means there is no answer to the problem

Step-by-step explanation:

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2 years ago
Use the multiplication property of exponents to determine if each statement is true or false.
lisabon 2012 [21]
1)
LHS:
{a}^{4}  \times  {a}^{3}  \times a \\  =  {a}^{4 + 3 + 1}  \\  =  {a}^{7}
LHS = RHS. So, the statement is true

2)
LHS:
{5}^{2}  \times  {3}^{4}  \\  = 25 \times 81 \\  =  {5}^{2}  \times  {9}^{2}  \\  =   {45}^{2}
LHS not equal to RHS. So, the statement is false

3)
LHS:
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LHS = RHS. So, the statement is true.

4)
LHS:
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7 0
3 years ago
Trevor was reading a book for a book report. Last week, he read 35 pages of the book. This week, he read 4.5 times as many pages
navik [9.2K]

9514 1404 393

Answer:

  see below

Step-by-step explanation:

Multiply the numbers as though they were integers, then mark off a number of decimal places in the product equal to the total number of decimal places in the numbers being multiplied (1).

6 0
3 years ago
-7 2/3 + (-5 1/2 ) + 8 3/4
Tanzania [10]

Answer:131/12

Step-by-step explanation:

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5 0
2 years ago
A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random
Akimi4 [234]

Answer:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

The degrees of freedom are given by:

df=n-1=14-1=13  

The p value for this case would be given by:

p_v =P(t_{(13)}  

Step-by-step explanation:

Information given

\bar X=24 represent the mean height for the sample  

s=2.2 represent the sample standard deviation

n=14 sample size  

\mu_o =25 represent the value that we want to test

t would represent the statistic

p_v represent the p value for the test

Hypothesis to verify

We want to cehck if the true mean is lees than 25 mph, the system of hypothesis would be:  

Null hypothesis:\mu \geq 25  

Alternative hypothesis:\mu < 25  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

The degrees of freedom are given by:

df=n-1=14-1=13  

The p value for this case would be given by:

p_v =P(t_{(13)}  

8 0
2 years ago
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