Answer:
With F represent the variable of interest:
Step-by-step explanation:
For this case we have a normal limits for the temperature Range. The minimum is 660 F and the maximum 790 F.
We can find the midpoint of this interval like this:
And the difference between the midpoint and the limits are:
So then we can create the following inequality:
With F represent the variable of interest.:
Answer:
C
Step-by-step explanation:
Answer:
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
---------------
-2x+2y+3z=0
-2x-y+z=-3
---------------- Subtract
3y + 2z = 3 Eqn A
=========================
-2x-y+z=-3
2x+3y+3z=5
---------------- Add
2y + 4z = 2
6y + 4z = 6 Eqn A times 2
------------------------------------ Subtract
-4y = -4
y = 1
-----------------
z = 0
-------------------
x = 1
Answer:
1800
Step-by-step explanation:
Labor quantity variance= Actual quantity ×standard price - standard quantity ×standard price
Standard quantity=2×2600=5200
Labor quantity variance
5050×12-5200×12=1800
Answer:
Step-by-step explanation:
