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postnew [5]
3 years ago
13

Analyze the table representing five experiments with an increasing number of trials. The table shows the frequency of a coin lan

ding heads up or tails up.
A 4-column table with 5 rows. Column 1 is labeled Experiment with entries 1, 2, 3, 4, 5. Column 2 is labeled Trials with entries 20, 40, 60, 80, 100. Column 3 is labeled Heads with entries 12, 25, 20, 35, 48. Column 4 is labeled Tails with entries 8, 15, 40, 45, 52.

What can you predict regarding the probability of the coin landing heads up?
A. The frequency does not change with more trials.
B. The experimental probability increases with more trials.
C. With more trials, the frequency of heads up will equal the frequency of tails up.
D. The frequency of heads up decreases with more trials.
Mathematics
2 answers:
sertanlavr [38]3 years ago
3 0

Answer:

C. With more trials, the frequency of heads up will equal the frequency of tails up.

Step-by-step explanation:

just took the test on edge

max2010maxim [7]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
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Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

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<span>x + 9 = 2(x - 1)^2
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Answer:

$149

Step-by-step explanation:

He spent 55 on sneakers at first, then he recieved 30 more, and gave 20 to the mom, which i added to the equation, and what he has left i also added.  

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