Answer:
For a function y = f(x), the range is the set of all the possible values of y.
In the question you wrote:
y = secx - 2
This can be interpreted as:
y = sec(x - 2)
or
y = sec(x) - 2
So let's see each case (these are kinda the same)
If the function is:
y = sec(x - 2)
Firs remember that:
sec(x) = 1/cos(x)
then we can rewrite:
y = 1/cos(x - 2)
notice that the function cos(x) has the range -1 ≤ y ≤ 1
Then for the two extremes we have:
y = 1/1 = 1
y = 1/-1 = -1
Notice that for:
y = 1/cos(x - 2)
y can never be in the range -1 < x < 1
As the denominator cant be larger, in absolute value, than 1.
Then we can conclude that the range is all reals except the interval:
-1 < y < 1
If instead the function was:
y = sec(x) - 2
y = 1/cos(x) - 2
Then with the same reasoning, the range will be the set of all real values except:
-1 - 2 < y < 1 - 2
-3 < y < -1
If the expression is what I understand it is, this is my answer. (x to the third times x to the negative sixth all squared)
First, i would simplify what is inside the parentheses. x^-6 is the equivalent to
1/x^6. Therefore, the expression inside the parentheses is a fraction: x^3/x^6.
When dividing numbers with exponents, just subtract the exponents.
3-6= -3 so the simplification of the expression in the parentheses is 1/x^3.
To finish the problem, I would apply the square from outside the parentheses to the values inside them. In this way, the exponent would be multiplied by 2.
Our final answer is 1/x^6.
Answer:
y=4/5x+5
Step-by-step explanation:
because this is the answer
For this case we have the following multiplication:
We can rewrite this multiplication in the following way:
From here, we apply the distributive property.
We have then:
Therefore, Jack's strategy is:
Write the number in an expanded form and then apply the distributive property.
Answer:
Jack's strategy is:
Write the number in an expanded form and then apply the distributive property.
