<span>
3x + 2y = 11</span>
<span />2(7x - y) = 2(3)
14x-2y=6
Adding both equations<span>
3x + 2y = 11</span>
<span>14x-2y=6</span>
<span>17x=17</span>
<span>x=1</span>
<span>substitute x = 1 in any equation</span>
<span>3(1) + 2y = 11</span>
<span>2y = 8</span>
<span>y = 4</span>
<span>Solution: x=1 y=4</span>
If the legs of a right triangle are a and b and the hypotnuse is c then
a²+b²=c²
so we are given
the legs are x and √7
and the hypotnuse is √19
so
x²+(√7)²=(√19)²
x²+7=19
minus 7 both sides
x²=12
sqrt both sides
x=√12
x=√(4*3)
x=(√4)(√3)
x=2√3