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egoroff_w [7]
4 years ago
12

This doesn't make any sense, and this is all the question is, no more then what I put.

Mathematics
1 answer:
AfilCa [17]4 years ago
5 0
Usually when a question is formatted this way without values for either variable, they want a literal equations olving for a varible, which is x in this case.

44x=l

Divide both sides by 44
x=l/44

Final answer: x=l/44
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What is the benchmark fraction of 7/10 x 16
katrin [286]
56/5. If I did this right that should be the answer.
6 0
3 years ago
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Help meee plz fast!!!!!!
Maurinko [17]

Answer: i dont know if im right nbut the answer is 4

Step-by-step explanation:

5 0
3 years ago
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Use the commutative property to write an equivalent expression 4(6) =
denpristay [2]

Answer:

this is an easy one. 6(4)

Step-by-step explanation:

since multiplication can be switched and you get the same answer, you can switch this using the communative property and you still get 24

7 0
3 years ago
Sandy ate 1/6 of a candy bar John ate 3/4 of it how much more of the candy bar did John eat them Sandy​
vlabodo [156]
7/12.

Explanation:

Find a common denominator between 3/4 and 1/6. Since both 6 and 4 can go into 12, that will be our denominator.

With 1/6, you have to multiple 6 by 2 to get 12, so multiple 1/6 by 2/2 and you get 2/12.

For 3/4, 4×3=12, so do 3/4 × 3/3 and you get 9/12.

Finally, subtract John's value from Sandy's, or 9/12-2/12 and you get 7/12, so he ate 7/12 more than Sandy.

Hope this helps :)
3 0
3 years ago
In a fund-raising game for your school, you bet $1 to roll two dice. If your total is 8,9,10 or 11 you win $2. If your total is
ololo11 [35]

Answer: E , You will lose 5.6 cents

Step-by-step explanation:

Because with two dice, there are 36 possible outcomes, 21 are 7 or less, 14 are 8 through 11, and 1 is twelve.

Also when you have a total of 8,9,10 or 11, you gain $1 deducing the $1 you bet. The same with when you have 12 you gain $5.

Average $ to gain when total is 8,9,10 or 11 = P(8,9,10,11)

P(8,9,10,11) = ($2-$1)(14/36) = $14/36 gain

P(12) = ($6-$1)(1/36) = $5/36 gain

P(7 or less) = (0-$1)(21/36) = -$21/36 loss

P(loss or gain)= P(8,9,10,11) + P(12) + P(7 or less)

P(loss or gain) = $( 14/36 + 5/36 - 21/36) = -$2/36

P(loss or gain) = -$0.056 = -5.6 cents loss

Therefore, For every $1 bet you will lose 5.6 cents.

8 0
3 years ago
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