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3 years ago

9

The radius of a circle is 1 meter. What is the area?

1 answer:

olchik [2.2K]3 years ago

6 0

Step-by-step explanation:

Area of Circle =

$\pi {r}^{2} \\ = \pi( {1}^{2} ) \\ = 1\pi \\ = \pi {m}^{2}$

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An animal shelter has 4/5 of its crates filled with animals. 1/2 of the filled crates are holding cats. What fraction of the tot

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It should be 2/5 because half of the 4/5 is cats

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4 years ago

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you download a video game on your computer. you have a 60-minute free trial of the game. it takes 5 1/6 minutes to set up the ga

iren2701 [21]

Answer:

B. $5\frac{1}{6}+(7\frac{1}{3})l \leq 60$

Step-by-step explanation:

Given,

The time for set up the game = $5\frac{1}{6}$ minutes,

Also, the time for each level of game is $7\frac{1}{3}$ minutes,

If there are l levels of games,

Then the time taken in all levels of game = $(7\frac{1}{3})l$

Hence, the total time ( in minutes ) = Set up time + time in all level

= $5\frac{1}{6}+(7\frac{1}{3})l$

We have 60-minute of free trial of the game,

So, the total time taken can not be exceed to 60 minutes,

$\implies 5\frac{1}{6}+(7\frac{1}{3})l \leq 60$

Which is the required inequality.

Option 'B' is correct.

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4 years ago

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Find the coefficient of x² in the expansion of (x - 2/x)⁶

Snowcat [4.5K]

Answer:

I think answer for ur question is 60

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3 years ago

U-substitutions only work for specific kinds of expressions. Below, you are asked to choose a value of n for which u-substitutio

Dahasolnce [82]

Answer:

Step-by-step explanation:

(a) $\int x^n e^{5x^4+1} \ dx$

Suppose $5x^4 + 1 = f$

by differentiation;

$\implies \ 20 x^3 dx = df --- (1)$

Suppose n = 3

Then, the integral

$I = \int x^ 3 e^{5x^4 + 1} \ dx$

$= \int e^f \ \dfrac{df}{20}$

$= \dfrac{1}{20} \int e^f \ dt$

$= \dfrac{1}{20} e^f + C$

recall that $f = 5x^4 + 1$

Then;

$\mathbf{ I = \dfrac{1}{20}e^{5x^4+1}+C}$

(b) $\int \dfrac{cos (\dfrac{1}{x^3})}{x^n } \ dx$

suppose; $\dfrac{1}{x^3} = f$

$x^3 = f$

$\implies -3x^{-4} \ dx = df$

$\implies \dfrac{1}{x^4} \ dx =-\dfrac{1}{3} df$

If n = u, then the integration is:

$I = \int \dfrac{1}{x^4} \ cos (\dfrac{1}{x^4}) \ dx$

$= \int -\dfrac{1}{3} \ cos \ f \ df$

$= -\dfrac{1}{3} \int \ cos \ f \ df$

$= -\dfrac{1}{3} \ sin \ f + C$

Since; $x^3 = f$

Then;

$\mathbf {I = -\dfrac{1}{3} \ sin \ \Big( \dfrac{1}{x^3}\Big) + C}$

(c) $\int \dfrac{x+n}{x^2 + 8x -4} \ dx$

Suppose $x^2 + 8x - 4 = f$

Then, by differentiation of both sides

$(2x + 8) \ dx = df$

$(x + 4) \ dx = \dfrac{1}{2} \ df$

Suppose n = 4 in integration, then:

$I = \int \dfrac{(x + 4) }{x^2 +8x -4} \ dx$

By substitution;

$I = \int \dfrac{1}{2}\dfrac{1}{f} \ df$

$= \dfrac{1}{2} \ \ { In |f|} + C$

$\mathbf{= \dfrac{1}{2} \ \ { In |x^2+8x -4|} + C}$

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3 years ago

What is the length of the base of a right triangle with an area of 20 square meters and a height of 4 meters?

Ilya [14]

Answer: i think its 80m.

Step-by-step explanation:

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3 years ago

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