Solve the system of equations algebraically. Verify your answer using the graph.

2 answers:

6 0

Both of those equations are solved for y. So if the first one is equal to y and the second one is equal to y, then the transitive property says that the first one is equal to the second one. We set them equal to each other and solve for x. 4x-5=-3 and 4x = 2. That means that x = 1/2. We were already told that y = -3, so the coordinates for the solution to that system are (1/2, -3), B from above.

KonstantinChe [14]3 years ago

5 0

Hello!

Since we already know the value of y we need to find x. We can plug in the y-value of -3 in the first equation and solve for x.

-3=4x-5
2=4x
x=1/2

This gives us the ordered pair (1/2,-3), so our answer is B. (1/2, -3).
.
I hope this helps!

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3 years ago

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The correct answer would be $\frac{-5 +/- \sqrt{13} }{2}$

In order to solve for this you must first get the equation equal to 0.

x^2=-5x-3 ----> add 5x to both sides.
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.

a = 1 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 3 (because it is the end number)

Now we can plug these values into the quadratic equation.

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$\frac{-5 +/- \sqrt{5^{2} - 4(3)(1) } }{2(1)}$

$\frac{-5 +/- \sqrt{13} }{2}$

And those would be your two answers.

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