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kobusy [5.1K]
3 years ago
7

What is the product of 4 2/3 and 11 1/4

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0

First you have to get rid of the mixed numbers, so multiply the whole numbers with the denominators and add the numerators so that way you get:

14/3 times 45/4....then cross simplify if possible and finally you can multiply the numerators and the denominators...

7/1 times 15/2 = 105/2....simplify it and get: 52 1/2


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The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0
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Answer:

C. 36

Step-by-step explanation:

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217 + 35 = 252 people

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