For this case we have the following kinematic equation that models the problem:
h (t) = (1/2) * (- 9.8) * t ^ 2 + 12 * t + 2
Rewriting we have:
h (t) = -4.9 * t ^ 2 + 12 * t + 2
When the ball hits the ground we have:
-4.9 * t ^ 2 + 12 * t + 2 = 0
Solving the polynomial we have:
t1 = -0.16
t2 = 2.61
We ignore the negative root because it is time.
Answer:
It will take the ball to hit the ground about:
t = 2.61 sec
2 is the output but I’m not sure make sure it is right
Answer:
11:9
Step-by-step explanation:
Since 11 comes first and 9 comes second, we do 11:9
Hree you have a small ( the clear triangle) inside a large one.
Area = shaded part = area of large triangle - area of the small clear triangle.
Area of a triangle = 1/2 * base * height
so we have area shaded part = 1/2 * 6 * 9 - 1/2 * 2 * 3
= 27 - 3 = 24 yd^2 Answer
