All categories

2 years ago

Explain Long division in your own words using at least 3 sentences.

Mathematics

2 answers:

m_a_m_a [10]2 years ago

8 0

Answer:

arithmetical division in which the divisor has two or more figures, and a series of steps is made as successive groups of digits of the dividend are divided by the divisor, to avoid excessive mental calculation.l

hope it helps

Marina86 [1]2 years ago

4 0

Answer:

form of devision that takes longer bc it a fraction or decimal. first you want to get rid of the decimals. then devide the numbers from the lowest to the highest

I may be wrong been for ever since I did it on paper

You might be interested in

No clue what to do here. Can anyone help???

ICE Princess25 [194]

Answer:

try the app socratic Step-by-step explanation:

8 0

3 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

2 years ago

Solve for x. x-17=-57<br> i need help

seraphim [82]

X - 17 = -57
-17. -17
x = -74

hope this helps xo

7 0

2 years ago

A train travelled from Dhaka to Darshana. The train took 5 hours and 30 minutes. The train travelled a distance of 327 kilometre

noname [10]

Answer:

59 kph

Step-by-step explanation:

The train goes 327 in 5 and 1/2 hours

So we do 327 / 5.5 = 59.49.....

Then we round down to get:

59 kpm

4 0

2 years ago

Planet ruba has a population of 1 million alien planet Zamba has one hundred thousand million how many more aliens does planet r

Elena-2011 [213]

Let's put it into numbers:

Ruba: 1 000 000

Zamba: 100 000 000 000

Zamba has many more aliens than Ruba!!!

it has 100 000 000 000/1 000 000 =100 000 times more aliens,

in absolute numbers: 100 000 000 000 - 1000 000 = =99 999 900 000

100 000 000 000
- 100 000
=99 999 900 000

7 0

2 years ago