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3 years ago

F(x) = x(2x/2)/x(x+5)(x+6)^2 Find the vertical asymptotes?

Mathematics

1 answer:

Alex Ar [27]3 years ago

7 0

Answer:

x = -5, x = -6

Step-by-step explanation:

After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.

$\displaystyle F(x)=\frac{x\frac{2x}{2}}{x(x+5)(x+6)}=\frac{x}{(x+5)(x+6)}$

The denominator will be zero when ...

x + 5 = 0 . . . . at x = -5

x + 6 = 0 . . . . at x = -6

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50 points + brainlest if you answer correctly

Mumz [18]

Answer:

5 is the value which makes the equation true .

Step-by-step explanation:

In this question we have provided an equation that is 9 ( 3x - 16 ) + 15 = 6x - 24 . And we are asked to write the steps to solve the equation with explanation  and to find the value of X .

Solution : -

$\longmapsto \quad \: 9(3x - 16) + 15 = 6x - 24$

Step 1 : Solving parenthesis on left side using distributive property which means multiplying 9 with 3x as well as -16 :

$\longmapsto \quad \:27x - \bold{144 }+ \bold{15 }= 6x - 24$

Step 2 : Solving like terms on left side that are -144 and 15 :

$\longmapsto \quad \:27x -129 = 6x - 24$

Step 3 : Adding 129 on both sides :

$\longmapsto \quad \:27x - \cancel{129} - \cancel{129} = 6x \bold{ - 24 } + \bold{129}$

Now on cancelling -129 with 129 on left side and solving the terms that are -24 and 129 on right side , We get :

$\longmapsto \quad \:27x = 6x + 105$

Step 4 : Subtracting with 6x on both sides :

$\longmapsto \quad \: \bold{27x} - \bold{6x} = \cancel{6x} +105 - \cancel{ 6x}$

On calculating further, We get :

$\longmapsto \quad \:21x = 105$

Step 5 : Now we are Dividing with 21 on both sides so that we can isolate the variable that is x :

$\longmapsto \quad \: \dfrac{ \cancel{21}x}{ \cancel{21}} = \dfrac{105}{ 21}$

Now , by cancelling 21 with 21 on left side , We get :

$\longmapsto \quad \:x = \cancel{\dfrac{105}{21}}$

Step 6 : Now our final step is to simplify the value of x that is 105/21 . We know that 21 × 5 is equal to 105 . So :

$\longmapsto \quad \: \purple{\underline{\boxed{\frak{ x = 5 }}}}$

Henceforth , value of x is 5

Verifying : -

Now we are verifying our answer by substituting value of x in the given equation . So ,

9 ( 3x - 16 ) + 15 = 6x - 24

9 [ 3 ( 5 ) - 16 ] + 15 = 6 ( 5 ) - 24

9 ( 15 - 16 ) + 15 = 30 - 24

9 ( -1 ) + 15 = 6

-9 + 15 = 6

6 = 6

L.H.S = R.H.S

Hence , Verified .

Therefore, our value for x is correct that means it'll makes the equation true .

<h2>#Keep Learning</h2>

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2 years ago

lawyer [7]

Answer:

Step-by-step explanation:

You multiply 14.1 times 14.1 and you get 198.81 which is the closest to 200

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3 years ago

Find the area of the semi circle plss

Pani-rosa [81]

The answer is 39.25

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3 years ago

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Help me i need to submit to my teacher by 8pm

Vladimir [108]

Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral. r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 - (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it. I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

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Name the prism in each case given that all lateral faces are rectangles and the bases are: Equilateral triangles

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This is a triangular prism.

The lateral faces are triangles; this means that the two bases are parallel to one another. This makes it a prism instead of a pyramid.

The bases being triangles makes it a triangular prism.

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