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GuDViN [60]
3 years ago
10

F(x) = x(2x/2)/x(x+5)(x+6)^2 Find the vertical asymptotes?

Mathematics
1 answer:
Alex Ar [27]3 years ago
7 0

Answer:

  x = -5, x = -6

Step-by-step explanation:

After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.

\displaystyle F(x)=\frac{x\frac{2x}{2}}{x(x+5)(x+6)}=\frac{x}{(x+5)(x+6)}

The denominator will be zero when ...

  x + 5 = 0 . . . . at x = -5

  x + 6 = 0 . . . . at x = -6

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ANSWER

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Or

3y+4x=16


EXPLANATION


Let us find the gradient of the line:

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We divide through by 4 now;


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This is now in the form;

y=mx+c

where

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This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of m=\frac{3}{4} .


Thus the perpendicular line has slope,

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Let the perpendicular line have equation,


y=mx+c

When we substitute the slope we have;


y=-\frac{4}{3}x+c

We substitute the point. (4,0) to find c.


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0=-\frac{16}{3}+c


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We substitute c to obtain;


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