Alvin is 14 years older than elga's The sum of their ages is 94 what is elga'ss age

(fx) = <br><img src="https://tex.z-dn.net/?f=%28fx%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20-%203x%20%2B%203%7D%20find%20f%28%20-%2013.

never [62]

$f(x)=\sqrt[3]{-3x+3}\\\\substitute\ the\ value\ of\ x\ to\ the\ equation:\\\\f(-13.6)=\sqrt[3]{-3(-13.6)+3}=\sqrt[3]{40.8+3}=\sqrt[3]{43.8}\approx3.525$

4 0

3 years ago

Mr. Alen has a tank of volume 450 cm3. Convert the volume into “m3

vladimir1956 [14]

Answer:

0.00045 $m^{3}$

Step-by-step explanation:

450 $cm^{3}$ ⇒ $m^{3}$

1 $cm^{3}$ = 0.000001 $m^{3}$

= 450 $cm^{3}$ = 450 × 0.000001 = 0.00045 $m^{3}$

7 0

2 years ago

Read 2 more answers

What is the most important lab safety rule

Diano4ka-milaya [45]

Answer:

The most important lab safety rule is to know the location of and how to use safety equipment, such as a fire extinguisher.

Step-by-step explanation:

Hope this helps you

Crown me as brainliest:)

8 0

2 years ago

Read 2 more answers

What is the ladder diagram of 27

Readme [11.4K]

Sorry can't answer that cause you need a diagram don't you?

6 0

3 years ago

Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre

choli [55]

Answer:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

$\hat p=\frac{46}{115}=0.4$ estimated proportion of people that have traded in their old car

$p_o=0.48$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:

Null hypothesis: $p\geq 0.48$

Alternative hypothesis: $p < 0.48$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.

4 0

3 years ago