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3 years ago

How to do this? I'm not sure.

Mathematics

1 answer:

Nady [450]3 years ago

7 0

U have to common factor that add up to -5 but times to 4 so basically the answer would be (x+5)(x-1)= 0 then you would get
x+5=0
x-1=0
both x’s are going to be different and have to equal to zero
x=-5
x=1

for the other one u just have to get two number that multiply to -49
x^2=-49
u square root the -49 and get -7 but u have to have both a positive and negative for 7
so
x=-7
x=7

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Two fractions have denominators of x^2+ 6x + 9 and x^2. What is the Least Common Denominator?

Gala2k [10]

SOLUTION

Write out the denominator of the fraction, we have

$\begin{gathered} x^2+6x+9 \\ \text{And } \\ x^2-9 \end{gathered}$

We want to obtain the least common denominator.

To do this, we need to factorize each of the expression given

$\begin{gathered} x^2+6x+9 \\ =x^2+3x+3x+9 \\ =x(x+3)+3(x+3) \\ =(x+3)(x+3) \end{gathered}$

Then we factorise the other fraction using difference of two square

$\begin{gathered} a^2-b^2=(a-b)(a+) \\ \text{Then} \\ x^2-9=x^2-3^2 \\ =(x-3)(x+3) \end{gathered}$

The the factorise expression becomes

$(x+3)(x+3)\text{ and (x-3)(x+3)}$

To obtain the least common denominator, we select the common factor and the product of the other factor,

Hence

$\begin{gathered} \text{common factor=(x+3)} \\ \text{The other factors are (x-3)(x+3)} \\ \text{Then } \\ \text{Least co}mmon\text{ denominator becomes } \\ (x+3)(x-3)(x+3) \end{gathered}$

Thus

The Least Common Denominator is (x +3)(x+3)(x-3) (Last Option )

5 0

1 year ago

Determine which ordered pair is a solution of y equals x plus two-fifths.. (1 point) the ordered pair (0, 0) the ordered pair (n

bulgar [2K]

The ordered pair (2,2 and two fifths)

3 0

3 years ago

Solve this system by substitution. y = 3 y = -3x + 6 *Remember to write your answer as a coordinate point (x, y). I

DochEvi [55]

Answer:

(1, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 3

y = -3x + 6

Step 2: Solve for x

Substitute in y: 3 = -3x + 6
[Subtraction Property of Equality] Subtract 6 on both sides: -3 = -3x
[Division Property of Equality] Divide -3 on both sides: 1 = x
Rewrite/Rearrange: x = 1

Step 3: Solve for y

Define original equation: y = -3(1) + 6
Multiply: y = -3 + 6
Add: y = 3

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3 years ago

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umka21 [38]

Answer:

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3 years ago