All categories

3 years ago

David drove a distance (d) of 187 km, correct to 3 significant figures.

Mathematics

1 answer:

Bogdan [553]3 years ago

7 0

Answer: 6.68km/litre

Step-by-step explanation:

Distance(d) = 187km ( to 3 significant figures)

Petrol(p) = 28litres ( to 2 significant figures)

A number, x, rounded to 1 significant figure is 200

Write down the error interval for x

Calculating the lower and upper bound for both 'd' and 'p'

Upper bound 'd' = 187.5km

Lower bound 'd' = 186.5km

Upper bound 'p' = 28.5km

Lower bound 'p' = 27.5km

Therefore,

Petrol consumption (C) = d/p

Upper C = 187.5 / 28.5 = 6.57894

Lower C = 186.5 / 27.5 = 6.781818

Accuracy answer for C = (6.57894 + 6.781818) / 2 = 6.680379

= 6.68km/ litre ( to 3 significant figures)

To achieve a reasonable level of accuracy, the upper and lower bounds of P and D was used to calculate C, which was then averaged.

Using 3 significant figures ensure that we capture the C better, instead of early rounding.

You might be interested in

What properties cannot be used in a proof

forsale [732]

I am certain the answer is C. Algebra properties are used in proofs. Postulates are definitely used. And definitions are explanations. So, it is C.

5 0

3 years ago

Round 3308.89 to the nearest australian dollar

const2013 [10]

Round 3308.89 to the nearest Australian dollar - $4336 AUD .

3 0

3 years ago

Bruce overdrew his checking account by $19, for which his bank charged him a $35 overdraft fee. If he deposits $60, what will hi

eimsori [14]

He overdrew his account by $19, so he is at $-19. His bank charges $35 fee. -19 - 35 = -54. He deposits $60, so 60 + (-54) = 6. He has $6 as his ending balance.

3 0

3 years ago

Read 2 more answers

19+4n<br><br> But "n=4"<br><br> IF YOU DON'T EXPLAIN OR PUT A FAKE ANSWER YOU WILL BE REPORTED

salantis [7]

Sub the number in
19 + 4(4)
= 19 + 16
= 35
multiplication is first because of bedmas

8 0

3 years ago

Read 2 more answers

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

2 years ago