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4 years ago

Which term is the perfect square of 3x^4

Mathematics

2 answers:

iragen [17]4 years ago

7 0

The answer is 9x^8
Hope it helped!!

AlekseyPX4 years ago

6 0

9x^8 is the answer for the problem

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The Davis family drove a total of 587 miles, starting on Friday and ending on Sunday. They drove 182 miles on Friday and 260 mil

valina [46]

Answer:

145

Step-by-step explanation:

Because what you want to do is add 260 to 182 then subtract from 587. I hope that helped! :)

8 0

3 years ago

Determine whether or not each relationship represents a function. explain your reasoning

Alekssandra [29.7K]

Answer:

left: yes
right: no

Step-by-step explanation:

A function maps an x-value to a single y-value. The graph of the parabola on the left does that.

The table on the right maps -1 to both 10 and 20, so does not meet the definition of a function.

7 0

3 years ago

Examine the required sample size needed to be able to

Xelga [282]

Answer:

$n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573$

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

$ME=2.33\frac{500}{\sqrt{2000}}=26.05$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=500$ represent the population standard deviation assumed

n represent the sample size (variable of interest)

Confidence =98% or 0.98

ME = 10 represent the margin of error desired

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =10 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.01;0;1)", and we got $z_{\alpha/2}=2.33$ , replacing into formula (b) we got: