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denis23 [38]
3 years ago
8

Which choices are equivalent to the fraction below check all the apply ""24" over 30

Mathematics
1 answer:
user100 [1]3 years ago
6 0

Answer:

c) The reduced form of the given fraction   \frac{24}{30} =  \frac{4}{5}

Step-by-step explanation:

Here, the given expression is  "24 over 30".

The given expression is  is equivalent to \frac{24}{30}

Now by Prime Factorization:

24  =  2 x 2 x 2 x 3

30  = 2 x 3 x 5

⇒ The common factors in 24 and 30 is  2 x 3  = 6

So, \frac{24}{30}  = \frac{2 \times 2 \times 2 \times 2 \times 3}{2 \times 3 \times 5}   = \frac{6 \times 4}{6 \times 5}   = \frac{4}{5}

Hence the reduced form of the given fraction   \frac{24}{30} =  \frac{4}{5}

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soldier1979 [14.2K]

Given :

Hight of the van from the ground, h = 3 feet.

The ramp into the van makes a 12° angle with the ground.

To Find :

How long is the ramp.

Solution :

Let, length of ramp is l .

So, height of ramp in terms of length is given by :

h = l \times sin\ 12^o\\\\l = \dfrac{h}{sin \ 12^o}\\\\l = \dfrac{3}{sin \ 12^o}\\\\l = 14.429 \ feet

Hence, this is the required solution.

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Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
How do I solve qudratic equations with factions, like this one:<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B3%7D%2
IceJOKER [234]
There are several approaches.

(5/3)x^2 - 5 = 0 has the coefficients a=5/3, b=0 and c = -5.

Thus, the quadratic formula would be appropriate here:

         -0 plus or minus sqrt(0^2 - 4(5/3)(-5) )
x  = -------------------------------------------------------
                                 2(5/3)
         plus or minus sqrt(100/3)
    = ------------------------------------
                         10/3
            3      10
     = ------* ----------- = sqrt(3)    (answer)
          10     sqrt(3)
8 0
2 years ago
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