Answer:
2nd option
Step-by-step explanation:
Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}
The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go
{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers
6/10
.6
If i'm wrong, sorry, haven't done this kind of stuff in a while
M(N+2)+3N+6
M*(n+2)+3(n+2)
Answer
(n+2)*(m+3)
Step-by-step explanation:
The gender of a child which is either a boy or a girl is determined by the XX-chromosomes, or XY-chromosomes.
Since the couple plan to have 5 children, the chance of a child being a boy is equal to the chance of it being a girl - the chances are 50/50.
What we do to achieve our aim is to run a simulation that would add an X or Y to an X for all 5 children.
Doing this 125 times, we obtain the number of trials we desire.
For each trial, we get for each child, C:
C1: X + (X or Y)
C2: X + (X or Y)
C3: X + (X or Y)
C4: X + (X or Y)
C5: X + (X or Y)
Since the chance of having an X is equal to the chance of having a Y, they equal probability, which is 0.5 for each.
Answer:
um i dont know
Step-by-step explanation:
