Answer:
Answer of 17 is ㏒(
+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is x = -㏒12/㏒8 and Answer of 39 is x = 5
Step-by-step explanation:
17. ㏒x + ㏒(x+15)
Using property ㏒a + ㏒b = ㏒a×b
∴ ㏒x + ㏒(x+15)
㏒x×(x+15)
㏒(
+15x)
The answer is ㏒(
+15x)
33. 2^(x-5) = 8
2^(x-5) = 2^3
Using property 2^a = 2^b
Then a = b
∴x-5 = 3
x = 8
The answer is x = 8
35. 2^x = 10
Taking log on both sides gives
㏒2^x = ㏒10
x×㏒2 = ㏒10
x = ㏒10/㏒2
The answer is x = ㏒10/㏒2
37. 8^-x = 12
Taking log on both sides gives
㏒8^-x = ㏒12
-x×㏒8 = ㏒12
x = -㏒12/㏒8
The answer is x = -㏒12/㏒8
39. 5(2^3 × x) = 8
5(8×x) = 8
x = 5
The answer is x=5
Answer:
260 gallons of lemonade
Step-by-step explanation:
Step one:
given data
We are told that Jada made 316 gallons of lemonade.
and later served 56gallons of the lemonade
Required
The remaining Lemonade
Step two
We have the total lemonade as 316
and the deducted as 56
the balance will be
= 316-56
=260 gallons of lemonade
The glee club could have 6 members so the 48 classical CDs would be divided into 8 and the 42 show tunes could be divided into 7