3 years ago

Lower Quartile value (Q1) is:41424648545657

Mathematics

2 answers:

qwelly [4]3 years ago

8 0

Answer:

Q1 =46

Step-by-step explanation:

Q1=(N+1)/4 (N means no of data)

=8+1/4

=9/4

=2.25

=2 nd term + (3 rd term - 2 nd term)

=44 +(46 - 44)

=44 + 2

=46

Anettt [7]3 years ago

3 0

The lower Quartile value should be from 42 to 48 i believe. I hope this help

You might be interested in

(1 pt)

LekaFEV [45]

B it is going to give you the answer

4 0

3 years ago

A hyperbola centered at the origin has a vertex at (0,−40) and a focus at (0, 41).

aniked [119]

$\frac{(x-h)^{2} }{a^{2} } - \frac{(y - k)^{2} }{b^{2} } = 1$

$\frac{(x-0)^{2} }{40^{2} } - \frac{(y - 0)^{2} }{b^{2} } = 1$

a² + b² = c²

40² + b² = 41²

b² = 41² - 40²

b² = 1681 - 1600

b² = 81

b = 9

slope (m) of asymptote = $+/-\frac{y}{x} = +/-\frac{b}{a} = +/-\frac{9}{40}$

y-intercept (b) = 0 since the center is at the origin

Answer: y = $\frac{9}{40}x$ and y = $-\frac{9}{40}x$

7 0

3 years ago

Read 2 more answers

If f(x)=3x + 2 and g(x)=2x - 2 what is (f-g)(x)?

omeli [17]

(3x+2)-(2x-2)
3x+2-2x-2
3x-2x=x
2-2+0
X

4 0

3 years ago

What is 489,493-763=?

Free_Kalibri [48]

Answer:

488,730

Step-by-step explanation:

Imagine you had 489,493 (anything) and you take away 763.

It would give you 488,730!

8 0

3 years ago

The graph of y = ax 2 + bx + c is shown below. Determine the solution set of 0 = ax 2 + bx + c.

Pavlova-9 [17]

On the graph, it's shown that the function has two real roots. This means that there will be two solutions. So the answer is 1. {0,4}

4 0

3 years ago

Read 2 more answers

Lower Quartile value (Q1) is:41424648545657​

Lower Quartile value (Q1) is:41424648545657