Answer:
Answer is first line
Step-by-step explanation:
-7(x+9) >= 37+3x
Going to solve for x:
-7x - 63 >= 37 + 3x
-7x - 3x >= 37 + 63
-10x >= 100
x <= 100/-10 (notice the change in equality because we divided by negative)
x <= -10
PEMDAS
15-(37+8)/3
15-45/3
15-15
0
answer is c ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Please check the picture.
