Answer:
679
Step-by-step explanation:
The formula for calculating the sum of an arithmetic progression which contains the first and the last term is expressed as;
Sn = n/2(a+l) where:
n is the number of terms in the series
a is the first term of the series
l is the last term of the series.
Given the series 3+10+......+87+94 which has 14terms,
a = 3
n = 14
l = 94
S3 = 14/2(3+94)
S3 = 7(97)
S3 = 679
Reducing 3 from numerator and denominator,
see below
dx 2+2xy 1 1 2 2
____ = ______ – ___x^2 – ____y^2 – _____x + ______y
dy 3 3 3 3 3
y=x-1
y=-2x-4
although I cant summon a graph for this one, I can give cords
for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)
For second graph the slope is down 2 over 1, and begins at (0,-4).
(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)