$~~(-3)^{-2}\\\\\\=\dfrac 1{(-3)^2}~~~~~~~~~~~~~~~~~~~~~~~~~;\left[k^{-n} = \dfrac 1{k^n},~~~ k \neq 0\right]\\\\\\=\dfrac 1{(-1)^2 \cdot 3^2}\\\\\\=\dfrac 1{1 \times 9}\\\\\\=\dfrac 19$

3 0

1 year ago

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I need help with this asap please! Any help will be appreciated!

pantera1 [17]

Answer:

n=3

Step-by-step explanation:

64^(1/3)

Note that the exponent 1/3 given stands for the third root of the integer.

64^(1/3) =4

Check: 4 x 4 x 4 = 64

(By comparison of 64^(1/3) to 64^(1/n) means n= 3)

∜(64^(1/3)) =∜(4) = 1.41421356

The real number is

All the roots are:

1.41421356

1.41421356i

−1.41421356

−1.41421356i

4 is not a perfect 4th power.

7 0

2 years ago