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Alinara [238K]
3 years ago
14

Consider the given matrix. 1 −1 0 5 1 4 0 1 1 Find the eigenvalues. (Enter your answers as a comma-separated list.) λ = Find the

eigenvectors. (Enter your answers in order of the corresponding eigenvalues, from smallest to largest by real part, then by imaginary part.)
Mathematics
1 answer:
fomenos3 years ago
3 0

Answer:

Step-by-step explanation:

We have to diagonalize the matrix

\left[\begin{array}{ccc}1&-1&0\\5&1&4\\0&1&1\end{array}\right]

we have to solve the expression

|A-\lambda I|=0

Thus, by applying the determinant we obtain the polynomial

(1-\lambda )^3+5-4=0\\(1-\lambda )^3+1=0\\

-\lambda^3+3\lambda^2-4\lambda+2

\lambda_1=1\\\lambda_2=1-i\\\lambda_3=1+i\\

and the eigenvector will be

v_1=(-4,0,5)\\v_2=(-1,-i,-1)\\v_3=(-1,i,1)

HOPE THIS HELPS!!

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When x = 5, the value of the expression –2(x – 10) is
nikitadnepr [17]

Answer:

The value of the expression at x=5 is 10

Step-by-step explanation:

The given expression is -2(x-10)

Let us simplify this expression.

Distribute -2 over the parentheses, we get

-2x+20

Now, substitute x = 5, we get

-2(5)+20

On simplifying, we get

-10+20\\=10

The value of the expression at x=5 is 10

8 0
4 years ago
Read 2 more answers
Lena's engagement ring has a radius of 9 millimeters. What is the ring's circumference? Use 3.14 for ​
scoray [572]

Answer:

Given - Radius of ring is 9 millimeters

To find - Circumference

Solution -

9 millimeters = 0.9 centimeters

Circumference of circle = 2 × pie × r

= 2 × 3.14 × 0.9

= 6.28 × 0.9

= 5.652

4 0
3 years ago
Please Help! The graph of y=f(x) is shown below. What are all of the real solutions of f(x)=0? (Picture of graph included)
qwelly [4]

Answer:

(7, 0), (-8, 0), (0, 0)

Step-by-step explanation:

y = f(x) = 0

the real solutions are the ones that cross the x-axis because when a point is on the x-axis, its y coordinate will be 0.

=> (7, 0), (-8, 0), (0, 0)

6 0
3 years ago
Which one is it plsss help
anzhelika [568]

Answer:

You are correct it is c

Step-by-step explanation:

6 0
3 years ago
Is (-1,2) a solution of the system y>x and x+y=>
valentina_108 [34]
(-1,2) is a solution

y>x

2>-1 is correct

in this case yes

x+y≥x

 -1+2≥-1 

1≥-1 is correct: Yes

in this case no

x+y≥y

1≥2 

is not correct. No


8 0
4 years ago
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