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3 years ago

Cancel oh we're on a shelf 1/3 of the cans fell off the show how many did not fall?

Mathematics

1 answer:

LenaWriter [7]3 years ago

4 0

Answer:

2/3

Step-by-step explanation:

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A pizza shop charged $49.57 for 3 large pepperoni pizzas. This price included a $2.50 delivery fee.

jek_recluse [69]

Answer:

$15.69

Step-by-step explanation:

subtract delivery fee: 49.58 - 2.5 = 47.07

divide by amount of pizzas: 47.07 / 3 = 15.69

8 0

3 years ago

Read 2 more answers

Which is the greater fraction<br>3/4 or 11/16

NARA [144]

Answer:

3/4

Step-by-step explanation:

3/4 = 75%

11/16 = about 68%

Therefore, 3/4 is greater

5 0

3 years ago

the graphy below shows the relationshio between the numbers of calories and the total amount in fat in different types of sandwi

taurus [48]

Answer:

The points have a positive trend and are most likely linear

Answer (C)

Step-by-step explanation:

∵ The graph represents the relation between the numbers

of calories and the total amount in fat in different types

of sandwiches

∵ Both values increase together

∴ Correlation is Positive

∵ If you draw the line best fit to check if it's strong or weak

Most of point will be on the line

∴ The points have a positive trend and are most likely linear

∴ The answer is (C)

3 0

3 years ago

Please show your work! Brainliest if you do

TiliK225 [7]

Answer:

$\frac{3x+4}{2x-2}$

Step-by-step explanation:

*photo attached*

8 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

Cancel oh we're on a shelf 1/3 of the cans fell off the show how many did not fall?​

Cancel oh we're on a shelf 1/3 of the cans fell off the show how many did not fall?