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iogann1982 [59]
3 years ago
8

Cancel oh we're on a shelf 1/3 of the cans fell off the show how many did not fall?​

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

2/3

Step-by-step explanation:

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A pizza shop charged $49.57 for 3 large pepperoni pizzas. This price included a $2.50 delivery fee.
jek_recluse [69]

Answer:

$15.69

Step-by-step explanation:

subtract delivery fee: 49.58 - 2.5 = 47.07

divide by amount of pizzas: 47.07 / 3 = 15.69

8 0
3 years ago
Read 2 more answers
Which is the greater fraction<br>3/4 or 11/16​
NARA [144]

Answer:

3/4

Step-by-step explanation:

3/4 = 75%

11/16 = about 68%

Therefore, 3/4 is greater

5 0
3 years ago
the graphy below shows the relationshio between the numbers of calories and the total amount in fat in different types of sandwi
taurus [48]

Answer:

The points have a positive trend and are most likely linear

Answer (C)

Step-by-step explanation:

∵ The graph represents the relation between the numbers

   of calories and the total amount in fat in different types

   of sandwiches

∵ Both values increase together

∴ Correlation is Positive

∵ If you draw the line best fit to check if it's strong or weak

  Most of point will be on the line

∴ The points have a positive trend and are most likely linear

∴ The answer is (C)

3 0
3 years ago
Please show your work! Brainliest if you do
TiliK225 [7]

Answer:

\frac{3x+4}{2x-2}

Step-by-step explanation:

*photo attached*

8 0
3 years ago
Two problems here I need solved! I need every step, so please have that with your answers!!
Free_Kalibri [48]
QUESTION 1

We want to solve,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}

We factor the denominator of the fraction on the right hand side to get,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.

This implies
\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}

We multiply through by LCM of
(x-4)(x - 2)

(x - 2) + x(x-4) = 2

We expand to get,

x - 2 + {x}^{2} - 4x= 2

We group like terms and equate everything to zero,

{x}^{2} + x - 4x - 2 - 2 = 0

We split the middle term,

{x}^{2} + - 3x - 4 = 0

We factor to get,

{x}^{2} + x - 4x- 4 = 0

x(x + 1) - 4(x + 1) = 0

(x + 1)(x - 4) = 0

x + 1 = 0 \: or \: x - 4 = 0

x = - 1 \: or \: x = 4

But
x = 4
is not in the domain of the given equation.

It is an extraneous solution.

\therefore \: x = - 1
is the only solution.

QUESTION 2

\sqrt{x+11} -x=-1

We add x to both sides,

\sqrt{x+11} =x-1

We square both sides,

x + 11 = (x - 1)^{2}

We expand to get,

x + 11 = {x}^{2} - 2x + 1

This implies,

{x}^{2} - 3x - 10 = 0

We solve this quadratic equation by factorization,

{x}^{2} - 5x + 2x - 10 = 0

x(x - 5) + 2(x - 5) = 0

(x + 2)(x - 5) = 0

x + 2 = 0 \: or \: x - 5 = 0

x = - 2 \: or \: x = 5

But
x = - 2
is an extraneous solution

\therefore \: x = 5
7 0
3 years ago
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