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1 year ago

9

Carlos is paid $17.90 per hour regularly. If he worked 45 hours last week, what was his gross pay? Carlos is paid at time-and-a-

half for overtime.

1 answer:

exis [7]1 year ago

3 0

Answer:

$ 850.25

Step-by-step explanation:

I will assume anything over 40 hours is 'overtime'

total pay will be

regular pay + overtime pay

17.90 * 40 hr + (17.90 * 1.5)(5hr) = $ 850.25

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A city bus collected $780 in fares on one day.

Brilliant_brown [7]

Answer:

450 people paid the discounted fare and 750 people paid the regular fare.

Step-by-step explanation:

let r be regular fares paid and d be discounted fares paid

Total fares = 0.8r + 0.4d = 780

Since 1200 people paid the fares,

r + d = 1200 = Total people

Rearrange this formula:

r = 1200 - d

Substitute r into Total Fares formula

Total fares = 0.8r + 0.4d

780 = 0.8(1200-d) + 0.4d

780 = 960 - 0.8d + 0.4d

780 = 960 - 0.4d

0.4d = 180

d = 450

Sub d=450 into Total people formula

r + d = 1200 = Total people

r + 450 = 1200

r = 1200-450

r = 750

450 people paid the discounted fare and 750 people paid the regular fare.

3 0

3 years ago

Read 2 more answers

La factorización de la expresión 33x^2-34x+8 es (3x-2)(11x-4)

USPshnik [31]

Answer:

B i think

Step-by-step explanation:

8 0

2 years ago

Jake rolls a six-sided die, numbered 1 to 6, five times. He rolls a 3 on two attempts.

matrenka [14]

I do believe that the answer to your question is 60%

4 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

22 points !!! multiply. express your answer as a fraction simplest form. 8.33 x 144

dem82 [27]

Answer:

99 24/25

Step-by-step explanation:

8.33*√144=

8.33*12=99 24/25 or 100 with 8.33 bar

8 0

3 years ago

Read 2 more answers