find the center of the circle that can be circumscribed about triangle EFG, E(6,4) F(6,2) and G(10,2)
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Answer:
<h2>140°</h2>solution,
Let <DEF= x°
<CDE= 2x°
<BAF= 90°
The sum of interior angle of hexagon= 720°
<A + <B + <C + <D + <E +<F = 720°
Again,
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