What is the greatest common factor of 44c5,22c3 and 11c4?
1 answer:
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Answer:
Colour | Probability
YELLOW | 0.20
WHITE | 0.18
GREEN | 0.12
RED | 0.18
BLUE | 0.32
Step-by-step explanation:
The complete question is presented on the attached image to this solution.
From the image of the spinner and the given probabilities, the combination of YELLOW, WHITE and GREEN make up exactly half of the total space on the spinner.
0.2 + 0.18 + 0.12 = 0.50
Then, BLUE and RED make up the other half of the spinner.
Probability of landing on either BLUE or RED = 1 - 0.50 = 0.50
Let P(BLUE) = x and P(RED) = y
x + y = 0.50
Two of the lines shown on the diagram are diameters of the circle.
The first line that is a diameter splits the circle into two parts; (WHITE, YELLOW, GREEN) and (RED, BLUE).
From here, we have established that x + y = 0.50
The other line that is a diameter splits The circle into two part; (WHITE, BLUE) and (YELLOW, GREEN, RED)
From this other information,
P(WHITE) + P(BLUE) = 0.50
0.18 + x = 0.50
x = 0.50 - 0.18 = 0.32
P(YELLOW) + P(GREEN) + P(RED) = 0.50
0.20 + 0.12 + y = 0.50
y = 0.50 - 0.32 = 0.18
To check, x + y = 0.32 + 0.18 = 0.50 (Correct!!)
Hope this Helps!!!
