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DENIUS [597]
3 years ago
11

Solve 2^(3x-4)=5 round to the nearest ten-thousandth

Mathematics
2 answers:
GaryK [48]3 years ago
4 0
2^(3x-4)=5
ln(2^(3x-4)=ln 5
(3x-4)ln 2=ln 5                    (log_a x^n=n*log_a x)
3x-4=ln 5/ln 2
3x=(ln 5 / ln 2)+4
x=[(ln 5 / ln 2)+4]/3
x≈2.1073

Answer:    x=[(ln 5/ln 2) +4]/3            (≈2.1073)
noname [10]3 years ago
3 0
You can use logarithm for this question:
If you convert the provided equation into logarithm, you should get:
Log _2 5= (3x-4)
You plug log_2 (5) into a calculator, I dont have one with me so you will have to do the calculation, then solve for x

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6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How
GenaCL600 [577]

By running in a bearing of 127°, Paul motion is in the south eastern direction.

Correct responses:

a. Please find attached the required diagram created with MS Visio

b. Paul's distance travelled east is approximately 11.98 km

  • Paul's distance travelled south is approximately 0.903 km

<h3>Method used for diagram and for the distance calculation</h3>

Given:

The distance Paul runs = 1.5 km

The bearing Paul is running = 127°

a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction

Please find attached the diagram representing the situation, created with MS Visio.

b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;

  • Paul's distance east =  15 km × cos(37°) ≈ <u>11.98 km</u>

Pau's distance travelled in the south direction relative to the starting point

is given by the vertical distance travelled relative to the x-axis, which is

given as follows;

Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>

Learn more about bearings in trigonometry here:

brainly.com/question/23427938

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