Solve 2^(3x-4)=5 round to the nearest ten-thousandth
2 answers:
2^(3x-4)=5 ln(2^(3x-4)=ln 5 (3x-4)ln 2=ln 5 (log_a x^n=n*log_a x) 3x-4=ln 5/ln 2 3x=(ln 5 / ln 2)+4 x=[(ln 5 / ln 2)+4]/3 x≈2.1073Answer: x=[(ln 5/ln 2) +4]/3 (≈2.1073)
You can use logarithm for this question: If you convert the provided equation into logarithm, you should get: Log _2 5= (3x-4) You plug log_2 (5) into a calculator, I dont have one with me so you will have to do the calculation, then solve for x
You might be interested in
Answer:
slide - translate
Step-by-step explanation:
you slided them both as neither of the figures changed
Answer:
7.1
Step-by-step explanation:
Using the distance formula
d = sqrt ( (x2-x1)^2 + ( y2-y1)^2)
sqrt ( (-5-2)^2 + ( -3- -2)^2)
sqrt( ( -7)^2 + ( -3 +2)^2)
sqrt( ( 49 + 1)
sqrt( 50)
7.071067812
To the nearest tenth
7.1
Answer: i think it’s no real solutions
Step-by-step explanation:
Answer: 17/22
Step-by-step explanation:
X = -m/b. Subtract z from both side and you get -m= bx Now divide both side by b and you get -m/b= x