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DENIUS [597]
3 years ago
11

Solve 2^(3x-4)=5 round to the nearest ten-thousandth

Mathematics
2 answers:
GaryK [48]3 years ago
4 0
2^(3x-4)=5
ln(2^(3x-4)=ln 5
(3x-4)ln 2=ln 5                    (log_a x^n=n*log_a x)
3x-4=ln 5/ln 2
3x=(ln 5 / ln 2)+4
x=[(ln 5 / ln 2)+4]/3
x≈2.1073

Answer:    x=[(ln 5/ln 2) +4]/3            (≈2.1073)
noname [10]3 years ago
3 0
You can use logarithm for this question:
If you convert the provided equation into logarithm, you should get:
Log _2 5= (3x-4)
You plug log_2 (5) into a calculator, I dont have one with me so you will have to do the calculation, then solve for x

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