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user100 [1]
3 years ago
13

I need this please help

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0
Function A has a rate of change of 0.75 while Function B has a rate of change of 0.25 so Function A has a greater rate of change.
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PLEASE HEP ASAP!!!!!!! 30 POINTS!!!!!
anzhelika [568]

Answer:

a) 42°F < x < 176°F

b) The inequality graph is attached.

c) No, This is because at 20° F benzene would not be in liquid form but in solid form.

Step-by-step explanation:

According to the Question,

a) For the benzene to remain in liquid form, the temperature of benzene must be less than the boiling point and greater than the boiling point. Let x be the temperature of benzene, For benzene to remain as liquid, its temperature must be between:

42°F < x < 176°F

b) The inequality graph is attached. The graph shows that the temperature of benzene must be between 42°F and 176°F so that it would be a liquid. The Closed circles represent that it is greater than 2.

c) No, This is because at 20° F benzene would not be in liquid form but in solid form. Because the temperature cannot go below 42 before it freezes, she would not have been able to conduct her research .

5 0
2 years ago
3×=18 what the answer to this problem
Luden [163]

Answer:

x=6

Step-by-step explanation:

Divide both sides by 3

7 0
2 years ago
Read 2 more answers
Given f(x)=4x^2−5 and g(x)=x+3 . What is (fg)(x) ?
zmey [24]
(fg)(x)=f(g(x))=4(g(x))²-5=4(x+3)²-5=4x²+24x+31
4 0
3 years ago
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7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​
serg [7]

Answer:

-\frac{x^2y^2}{2}

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}

Multiply the numerators :

\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}

Multiply the denominators :

\frac{-18x^6y^4z^3}{36x^4y^2z^3}

Apply the negative rule :

-\frac{18x^6y^4z^3}{36x^4y^2z^3}

Cancel the common factor which is 18 :

-\frac{x^6y^4z^3}{2x^4y^2z^3}

Apply the addition exponent rule :

\frac{y^4z^3x^{6-4} }{2y^2z^3}

Subtract :

\frac{x^2y^4z^3 }{2y^2z^3}

Apply the rule for y :

\frac{x^2y^{4-2} z^3 }{2z^3}

Subtract :

\frac{x^2y^2z^3 }{2z^3}

Cancel the common factor of z^3 :

-\frac{x^2y^2}{2}

5 0
2 years ago
PLEASE HELP IS THIS RIGHT??????????AND EXPLAIN PLZZ
Anit [1.1K]
Add like terms

-4x+x=-3x
6-2=4

So the simplified term is 4-3x
6 0
3 years ago
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