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user100 [1]
3 years ago
13

I need this please help

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0
Function A has a rate of change of 0.75 while Function B has a rate of change of 0.25 so Function A has a greater rate of change.
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Events A and B are independent. find the missing probability<br> P(A)= 1/4 , P(B)= 3/5, P(B I A) =?
Svetach [21]

Answer:

hello : P(A and B) = 3/20

Step-by-step explanation:

events A and B are independent:

P(A and B) = P(A)×P(B)

P(A and B) = (1/4)×(3/5)

P(A and B) =3/20

continu ....

P(B/A)= P(A and B) / P(A)

3 0
4 years ago
LAST ATTEMPT! MARKING AS BRAINLIEST! PLEASE <br><br> Algebra topic is on logarithms
xenn [34]

Answer:

Step-by-step explanation:

Not entirely sure about the first one, but I'll try the others:

2- log base 8 (8x) = log base 8 (8) + log base 8 (x) = 1 + log base 8 (x)

3 - log base 3 (5^x) = x log base 3 (5)

4 - log base 2 (5/x) = log base 2 (5) - log base 2 (x) = In 5 - In x

5 - log base 2 (2^x) = x log base 2 (2) = x · 1 = x

3 0
3 years ago
I dont understand this question 2/5÷9/4 is the same as which of the following?​
OLga [1]

Answer:

Step-by-step explanation:

You didn't list anything to choose from.

2/5÷9/4 When you have a division and fraction after it, change the sign to multiplication and flip the fraction.

2/5 * 4/9

8/45

4 0
3 years ago
Simplify 4(2x^3y^4)^4/2(2x^2y^6)^3. Show your work. Please help ASAP!!
vovikov84 [41]

Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

=2[2^{4-3}x^{12-6}y^{16-18}]( using the property a^m.a^n=a^{m+n} )

=2[2^1x^6y^{-2}]

=\frac{4x^6}{y^2} ( using the property a^m=\frac{1}{a^{-m}} )

Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

5 0
3 years ago
Can you help me with this?
antiseptic1488 [7]

Answer: C

Step-by-step explanation:

7 0
3 years ago
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