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vodomira [7]
3 years ago
13

Someone help, please!​

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

(0,3) is one of them but i'm unsure what the other one is

Step-by-step explanation:

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What statement complete the proof below given 3x+ 7=x-5
Advocard [28]

Proof: x=-6

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Elevii au studiat o schiță a corpului uman. Ei au observat că ar putea trasa pe schiță un
julia-pushkina [17]

Answer:

an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).

8 0
3 years ago
What the volume is of this solid
mrs_skeptik [129]

Answer:

336.

Step-by-step explanation:

8 x 7 x 6 = 336.

Feel free to let me know if you need more help! :)

5 0
3 years ago
Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the kite? Round to the nearest tenth. 10.6 unit
Archy [21]

<u>Answer-</u>

<em>Perimeter of the kite is </em><em>16.2 units</em>

<u>Solution-</u>

As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY

So, perimeter of the kite WXYZ is,

=2(\overline{WX}+\overline{WZ})

And

\overline{WX}=\sqrt{(1-3)^2+(1-4)^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}

\overline{WZ}=\sqrt{(1-3)^2+(1+3)^2}=\sqrt{(-2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}

So, perimeter will be,

P=2(\sqrt{13}+\sqrt{20})=16.15\approx 16.2\ units

4 0
3 years ago
Read 2 more answers
What’s the answer to the top question and steps how to solve?
Leviafan [203]

Answer:

-3.69

Step-by-step explanation:

Exponential equations can be solved by taking Ln (natural logarithm) of both sides. The rule we need to know is:

Ln(a^b)=bLn(a)

Now lets work out this problem:

16^{2x+3}=13^{x-1}\\Ln(16^{2x+3})=Ln(13^{x-1})\\(2x+3)Ln(16)=(x-1)Ln(13)

Using calculator, we take the values of Ln 16 and Ln 13 as:

Ln 16 = 2.7726

Ln 13 = 2.5649

Now, we can solve for x:

(2x+3)Ln(16)=(x-1)Ln(13)\\(2x+3)2.7726=(x-1)2.5649\\5.5452x+8.3178=2.5649x-2.5649\\2.9803x=-10.8827\\x=-3.69

x is -3.69 (rounded to 2 decimal places)

3 0
3 years ago
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