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emmasim [6.3K]
3 years ago
11

What to do from here? (Please don't solve)

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0
You have the answer if you just do a little bit more but other than that you have your answer

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4 - 3x = 8 - 4x Plz answer this question
timurjin [86]

Answer:x=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4−3x=8−4x

4+−3x=8+−4x

−3x+4=−4x+8

Step 2: Add 4x to both sides.

−3x+4+4x=−4x+8+4x

x+4=8

Step 3: Subtract 4 from both sides.

x+4−4=8−4

x=4

8 0
3 years ago
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What is the circumference of the circle? 11 m​
-BARSIC- [3]
C=2πr r radius it would be right
3 0
3 years ago
literally a free 50 points, just need the answer, What is the solution to the equation fraction 4 over 5 n minus fraction 1 over
AleksandrR [38]

Answer:

n = 1/2

Step-by-step explanation:

So the equation is 4/5n - 1/5 = 2/5n.

So, the first thing that we need to do is get the variable on one side.

So, to do that we need to subtract 4/5n on both sides.

Now our equation is -1/5 = -2/5n

Now the last step is to simplify.

To do that, we need to multiply by the reciprocal of 2/5 on both sides.

That leaves us with 1/2 = n

6 0
3 years ago
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Maddox McDonald A caterpillar moves across the grass at a rate of 4 2/3 feet every 7 minutes. How fast does the caterpillar move
harina [27]

Answer: 2/3 feet per minute

Step-by-step explanation:

From the question, we are informed that a caterpillar moves across the grass at a rate of 4 2/3 feet every 7 minutes.

The rate at which the caterpillar move in feet per minute will be:

= 4 2/3 ÷ 7

= 14/3 ÷ 7

= 14/3 × 1/7

= 14/21

= 2/3 feet per minute

8 0
3 years ago
Solve each system help please!!!!!
nexus9112 [7]

12)\\\left\{\begin{array}{ccc}y=-2x+3&(*)\\2x+5y=7\end{array}\right\qquad\text{put}\ (*)\ \text{to the second equation}\\\\2x+5(-2x+3)=7\qquad\text{use distributive property}\\2x+(5)(-2x)+(5)(3)=7\\2x-10x+15=7\qquad\text{subtract 15 from both sides}\\-8x=-8\qquad\text{divide both sides by (-8)}\\\boxed{x=1}\\\\\text{Put the value of x to}\ (*)\\\\y=-2(1)+3\\y=-2+3\\\boxed{y=1}\\\\Answer:\ x=1,\ y=1\to(1,\ 1)

14)\\\left\{\begin{array}{ccc}x=y-4&(*)\\x-2y=-6\end{array}\right\qquad\text{put}\ (*)\ \text{tu the second equation}\\\\(y-4)-2y=-6\\y-4-2y=-6\qquad\text{add 4 to both sides}\\-y=-2\qquad\text{change the signs}\\\boxed{y=2}\\\\\text{Put the value of y to}\ (*)\\\\x=2-4\\\boxed{x=-2}\\\\Answer:\ x=-2,\ y=2\to(-2,\ 2)

16)\\\left\{\begin{array}{ccc}x=-4y+3&(*)\\5x-3y=-31\end{array}\right\qquad\text{put}\ (*)\ \text{to the second equation}\\\\5(-4y+3)-3y=-31\qquad\text{use distributive property}\\(5)(-4y)+(5)(3)-3y=-31\\-20y+15-3y=-31\qquad\text{subtract 15 from both sides}\\-23y=-46\qquad\text{divide both sides by (-23)}\\\boxed{y=2}\\\\\text{Put the value of y to }\ (*)\\\\x=-4(2)+3\\x=-8+3\\\boxed{x=-5}\\\\Answer:\ x=-5,\ y=2\to(-5,\ 2)

3 0
3 years ago
Read 2 more answers
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