( Which word from List 1 BEST completes this analogy?

Which statements are true about the trapezoid? not sure if i’m right

taurus [48]

Yes you are absolutely right

8 0

3 years ago

State the practical meaning of the slope and y-intercept for the situation described. The cost, in dollars, of retaining the ser

Anuta_ua [19.1K]

The practical meaning of the slope and y - intercept of the linear equation, C = 48x + 18 is that 48x is the variable cost depending on the number of hours and 18 is the fixed cost or the overhead change. Hence, the answer to the question above is letter A.

6 0

3 years ago

Read 2 more answers

Which graph correctly represents 5/2x-y< 3

kompoz [17]

5/2x - y < 3
Add y
5/2x < 3 + y
Subtract 3
5/2x - 3 < y
y > 5/2x - 3
Graph "5/2x - 3" and shade the area that is above it

5 0

3 years ago

In 2003 a town’s population was 1431. By 2007 the population had grown to 2134. Assume the population is changing linearly.How m

sergiy2304 [10]

We will have the following:

First, we will have that the population change by:

$\Delta P=2134-1431\Rightarrow\Delta P=703$

So, the population changed by 703 people.

It took the follwoing number of years to change from 1431 to 2134:

$\Delta y=2007-2003\Rightarrow\Delta y=4$

So, it took 4 years to changes from 1431 to 2134.

$m=\frac{2134-1431}{2007-2003}\Rightarrow m=175.75$

The average population growth per year is of 175.75 people per year.

The population in 2000 would have been:

$P_{2000}=\frac{2000\cdot1431}{2003}\Rightarrow P_{2000}=1428.856715\ldots$

$\Rightarrow P_{2000}\approx1429$

So, the population in 2000 would have been approximately 1429 people.

We will have that the equation for the population would be:

$P=(\frac{2134-1431}{2007-2003})t+1429\Rightarrow P=\frac{703}{4}t+1429$

So, the equation would be:

$P=175.75t+1429$

Now, we predict the number of people of the town in 2014:

$P_{2014}=175.75(14)+1429\Rightarrow P_{2014}=3889.5$

$\Rightarrow P_{2014}\approx3890$

So, there will be approximately 3890 people of the town in 2014.

3 0

1 year ago

4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail

Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

$h^{-1}(x)=\sqrt{\frac{x+1}{3}}$ ⇒ answer D

Step-by-step explanation:

* Lets explain how to find the inverse of a function

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = $f^{-1}(x)$

* Lets use these steps to solve the problems

∵ $f(x)=\sqrt{x-3}$

∵ f(x) = y

∴ $y=\sqrt{x-3}$

- Exchange x and y

∴ $x=\sqrt{y-3}$

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by $f^{-1}(x)$

∴ $f^{-1}(x)=x^{2}+3$

∵ g(x) = x² + 3

∴ $f^{-1}(x)=g(x)$

∴ The functions are inverses to each other

* Now lets find f(g(x))

- To find f(g(x)) substitute x in f(x) by g(x)

∵ $f(x)=\sqrt{x-3}$

∵ g(x) = x² + 3

∴ $f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x$

∴ f(g(x)) = x

∴ The functions are inverses; f(g(x)) = x

* Lets find the inverse of h(x)

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ $\frac{x + 1}{3}=y^{2}$

- Take √ for both sides

∴ ± $\sqrt{\frac{x+1}{3}}=y$

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ $\sqrt{\frac{x+1}{3}}=y$

- replace y by $h^{-1}(x)$

∴ $h^{-1}(x)=\sqrt{\frac{x+1}{3}}$

4 0

3 years ago