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Paha777 [63]
3 years ago
13

What is the equation for the line that passes through the points (-5, 2) and (5,-6)?​

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

4x + 5y = -10 or y = -⅘x - 2

Step-by-step explanation:

First, find the <em>rate</em><em> </em><em>of change</em><em> </em>[<em>slope</em>]:

-y₁ + y₂\-x₁ + x₂ = m

\frac{ -2 - 6}{5 + 5}  =  - \frac{8}{10}  =  - \frac{4}{5}

Then use the Point-Slope Formula since we are given points. Now, according to this formula, all negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY careful inserting the coordinates into the formula with their CORRECT signs. It does not matter which one you choose:

y - y₁ = m(x - x₁)

y + 6 = -⅘(x - 5)

y + 6 = -⅘x + 4

- 6 - 6

_______________

y = -⅘x - 2

If you want it in <em>Standard Form</em>:

y = -⅘x - 2

+⅘x +⅘x

___________

⅘x + y = -2 [We do not want fractions in our Standard Equations, so multiply by the denominator to get rid of it.]

5[⅘x + y = -2]

4x + 5y = -10 >> Line in Standard Form

__________________________________________________________

y - 2 = -⅘(x + 5)

y - 2 = -⅘x - 4

+ 2 + 2

______________

y = -⅘x - 2

y = -⅘x - 2

+⅘x +⅘x

___________

⅘x + y = -2 [We do not want fractions in our Standard Equations, so multiply by the denominator to get rid of it.]

5[⅘x + y = -2]

4x + 5y = -10 >> Line in Standard Form

** You see? I told you that it would not matter which ordered pair you choose because you will always get the exact same result!!!

I am joyous to assist you anytime.

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2 years ago
Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0
fomenos

• The value of the discriminant ,D= -16

,

• The solution to the quadratic equation is

x=\frac{1+2i}{5}\text{     or    }\frac{1-2i}{5}

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

,

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}

Note that:

√-1 = i

x=\frac{2\pm\sqrt[]{16\times-1}}{10}

x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}x=\frac{2\pm4i}{10}x=\frac{2}{10}\pm\frac{4i}{10}x=\frac{1}{5}\pm\frac{2}{5}ix=\frac{1\pm2i}{5}

That is;

\text{Either x=}\frac{1+2i}{5}\text{ or     x=}\frac{1-2i}{5}

7 0
1 year ago
Expand and simplify pla
k0ka [10]
Y = f(3f - 4g + 3) +7g(3f - 4g + 3)
= 3f^2 - 4fg + 3f + 21fg - 28g^2 + 21g
= 3f^2 + 3f + 17fg + 21g - 28g^2
4 0
2 years ago
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